Answer:
x = 5 and y = 7
Step-by-step explanation:
Given that,
PT = x+2, TR=y, QT=2x, TS=y+3
We need to find the value of x and y.
The diagonal of a parallelogram bisect each other. It means,
PT = TR and QT = TS
ATQ,
y = x+2 ...(1)
and
y+3 = 2x ....(2)
Subtracting equation (1) and (2).
y-(y+3) = x+2-2x
y-y-3 = 2-x
-3 = 2-x
x = 2+3
x = 5
Put the value of x in equation (1).
y = 5 + 2
y = 7
Hence, the values of x and y are x = 5 and y = 7.
The GCF is 1. There is no other number that those numbers have in common.
Hope this helps!!
Answer: 38
Step-by-step explanation: to evaluate an expression for these variables, plug in those numbers for the variables.
Plugging in -1 for y and -19 for z gets you this:
-2(-1)^2(-19)
Now simplify according to order of operations (PEMDAS - parenthesis exponents multiplication/division addition/subtraction)
-1^2 = 1
-2(1) = -2
-2(-19) = 38
Your answer is 38
Answer:
7.)C
8.)B
9.)B
10.)D (I think)
11.)B (yet again I think)
I'm not 100% sure on the last two
hope this helped
