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lilavasa [31]
3 years ago
5

Solve. 4/7 = 21/ x - 3

Mathematics
2 answers:
kicyunya [14]3 years ago
7 0

4/7 = 21/ (x - 3)


multiply by (x-3) on each side

4(x-3)/7 =21

multiply by 7 on each side

4(x-3) = 21*7

distribute

4x-12 = 147

add 12 to each side

4x = 159

divide by 4

x = 159/4

change back to a mixed number

4 goes into 159 39 times with 3 left over

39 3/4

Choice C

PtichkaEL [24]3 years ago
4 0
4/7 = 21/(x-3)

Multiply x-3 on to both sides to get

4(x-3)/ 7 =21

Multiply both sides by 7 to get

4(x-3) = 144

Multiply to get

4x - 12 = 144

Add 12 on both sides to get


4x = 156

Divide both by 4 to get

156/4

Or

39
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Jake and his dad are making flags for a scouting project.They are going to make(6,12,18) flags . Each flag takes (2/3,3/4,5/6) o
evablogger [386]

Answer:

The total yards of cloth needed for the flags = 28

Step-by-step explanation:

Given:

Jake and his dad are making (6,12,18) different types of flags.

Each flag takes (\frac{2}{3},\frac{3}{4},\frac{5}{6}) of a yard of cloth.

To find the total yards of cloth needed in all.

Solution:

Flag A :

Each flag requires = \frac{2}{3} of a yard of cloth

Total number of this flag = 6

Total cloth required for this flag = \frac{2}{3}\times 6 = 4\ yd

Flag B:

Each flag requires = \frac{3}{4} of a yard of cloth

Total number of this flag = 12

Total cloth required for this flag = \frac{3}{4}\times 12 = 9\ yd

Flag C:

Each flag requires = \frac{5}{6} of a yard of cloth

Total number of this flag = 18

Total cloth required for this flag = \frac{5}{6}\times 18 = 15\ yd

Thus, total yards of cloth needed for the flags = 4\ yd+9\ yd+15\ yd =28\ yd

8 0
4 years ago
Free answers if u want
vladimir2022 [97]

Answer:

Thank you so much!!!

Step-by-step explanation:

3 0
3 years ago
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keisha is walking around a track that is 400 yards long. she has walked around the track 5 times so far. how many more yards doe
daser333 [38]
3 more times hope I helped
6 0
4 years ago
The driver of a 810.0 kg car decides to double the speed from 23.6 m/s to 47.2 m/s. What effect would this have on the amount of
Setler [38]

Answer:

  • KEi = 2.256×10^5 J
  • KEf = 9.023×10^5 J
  • 4 times as much work

Step-by-step explanation:

The kinetic energy for a given mass and velocity is ...

  KE = (1/2)mv^2 . . . . . m is mass

At its initial speed, the kinetic energy of the car is ...

  KEi = (1/2)(810 kg)(23.6 m/s)^2 ≈ 2.256×10^5 J . . . . . m is meters

At its final speed, the kinetic energy of the car is ...

  KEf = (1/2)(810 kg)(47.2 m/s)^2 ≈ 9.023×10^5 J

The ratio of final to initial kinetic energy is ...

  (9.023×10^5)/(2.256×10^5) = 4

4 times as much work must be done to stop the car.

_____

You know this without computing the kinetic energy. KE is proportional to the square of speed, so when the speed doubles, the KE is multiplied by 2^2 = 4.

8 0
3 years ago
Angle GHI and angle JHI are supplementary. Angle GHI measures (28x + 40)° and angle JHI measures (7x)°. What is the measure of a
muminat

Two angles are supplementary if their sum is 180 degrees.

Here we are given:

Angle GHI measures (28x + 40)° and angle JHI measures (7x)°.

Sum of angle GHI and JHI is 180.

angle GHI + angle JHI = 180

(28x + 40) + (7x) = 180

35x = 140

dividing both sides by 35,

x=4

Now let us find angle JHI

angle JHI = 7x = 7*4 =28

Answer : Angle JHI is 28 degrees.


4 0
4 years ago
Read 2 more answers
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