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mote1985 [20]
3 years ago
11

- 3√45-√ 125 + √200-√150

Mathematics
2 answers:
andrezito [222]3 years ago
8 0

Answer:

=-80-5√5

this is the answer

hope this helps

Murljashka [212]3 years ago
4 0
-29.4102647752 the answer I think
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What is the value of b2-4ac for the following equation? 5x2+7x=6​
poizon [28]

Answer:

169

Step-by-step explanation:

Given data

The function is

5x^2+7x=6​

rearrange

5x2+7x-6=0

From the above expression, we can see that

a=​5

b=7

c=-6

Substitute into the expression b^2-4ac

=7^2-4*5*-6

= 49-(-120)

=49+120

=169

Hence the answer is 169

8 0
3 years ago
paul earned 175 for working 5 days last week. He earned the same amount each day. What was pauls pay rate?
andre [41]

Answer:

His pay rate is $35.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
4 ^-3 rewrite without an exponent
hichkok12 [17]

Answer:

(1/4)³

Step-by-step explanation:

Hope it helps you

5 0
3 years ago
Read 2 more answers
G = f - d / v what is f
Ratling [72]

Answer:

f = g + d/v

Step-by-step explanation:

g = f - d/v

add d/v to both sides

g + d/v = f

switch sides

f = g + d/v

3 0
3 years ago
Simplify 3(x-4)+8(x+2) A) 11x-4 B)11x+4 C)11x-2
swat32
It is depending upon multiplication of values to variable and values of numbers again. Here the answer is Option B) 11x + 4. Here is my process on this equating expression.

For this we have to apply the law of distribution or the distributive law, in this we distribute the parentheses into the brackets to further expand them, we further eliminate the bracketed groups and perform the calculations. So, it is stating that, for any number, variable or a quantity if multiplied into a bracketed expression yields two products of multiplication of two quantities; one being the first quantity outside the brackets and two separately distinguished quantities inside the brackets. They are furthermore subtracted by the first quantity to that of the second quantity to obtain and achieve the distributive law.

If I were to express it through mathematical LaTeX Expressions, it will be represented as the first quantity as a variable of "a" where it can exhibit a value or a variable or a term or rule, etc. and then inside the brackets represented as "b" and "c".

Performing the law of distribution of values, variables, etc. It is demonstrated as:

\boxed{\mathbf{a \times (b - c) = a \times b - a \times c}}

We are given the values of the variables as a separate context and addition of two expressions. So, for both of them:

\mathbf{First \: \: Expression: \: 3 (x - 4)}

\mathbf{Second \: \: Expression: \: 8 (x + 2)}

Apply the following distribution law to expand the values onto variables and numbered values inside the brackets.

So, the variable "a", "b" and "c"; For First Expression is: a = 3, b = x and c = 4.

And, Similarly, for the variable of "a", "b" and "c", For Second Expression is: a = 8, b = x and c = 2.

Therefore, According to our distributive law of expanding the components will directly yield us:

\mathbf{3 \times x - 3 \times 4 + 8 \times x + 8 \times 2}

\mathbf{3x - 12 + 8x + 16}

Regroup the terms for a better visualisation and a clearer understanding for similarities between the terms; it makes it more easier to proceed further. So:

\mathbf{3x + 8x - 12 + 16}

All we did, was to separate the variable attached numbered values and shift it on one side; And, separating or shifting the values without variables to the other side.

\mathbf{11x - 12 + 16}

\boxed{\huge{\mathbf{Required \: \: Answer: \: 11x + 4}}}

Hope it helps.
7 0
3 years ago
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