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3 years ago

AB=4x+3 and CD=24+5x find bc

Mathematics

1 answer:

madam [21]3 years ago

6 0

Answer:

Step-by-step explanation:

1. use distribution factor

(4x+3)(24+5x)

4x times 24 = 96

4x times 5x = 20x

3 times 24 = 72

3 times 5x = 15x

2. combine like terms

96 + 72 = 168

15x + 20x = 35x

35x + 168 or 168 + 35x

I may be wrong please check my answer. I may have a lapse in my algebra, or I may have misunderstood the problem. But this is what I can give you to the best of my knowledge.

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Answer:

The amount of phosphorus-32 left after 100.1 days is <u>9.3 g</u>.

Step-by-step explanation:

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Initial amount of Phosphorus-32 is, $N_0=1200\ g$

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Half life of the block is, $t_{1/2}=14.3\ days$

Now, final amount left is, $N=?$

We know that, the decay equation for a radioactive material is given as:

$N=N_0e^{-kt}\\k\to decay\ constant$

The value of the decay constant is given as:

$k=\frac{\ln 2}{t_{1/2}}\\\\k=\frac{0.693}{14.3}=0.0485$

Now, plug in all the given values and calculate 'N'. This gives,

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Therefore, the amount of phosphorus-32 left after 100.1 days is 9.3 g

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3 years ago