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m_a_m_a [10]
3 years ago
9

Which of the following numbers is rational but not an integer A.0 B.3 C.-9 D.-4.3

Mathematics
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

Thus, every integer is a rational number. Clearly, 3/2,-5/3, etc. are rational numbers but they are not integers. Hence, every integer is a rational number but a rational number need not be an integer.

Step-by-step explanation:

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Write 35/3 as a mixed number.
labwork [276]

Answer:

Answer is 11⅔

Step-by-step explanation:

if want convert improper fraction into mixed number you have divide numerator by denominator

35÷3=11 remainder 2

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Dennis traveled at an average speed of 60 mph on his vacation trip. How far did he travel in the first 4.5 hours
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A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1690 feet, what are the dimensions o
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6 0
4 years ago
Which of these expressions is a monomial?
Margarita [4]
A monomial has one term. Therefore, A is the only one with one term.
7 0
3 years ago
Read 2 more answers
Y=x² + 16x + 64
motikmotik

I'll do the first one to get you started

The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64

Compare that to y = ax^2+bx+c and we see that

a = 1

b = 16

c = 64

Use the values of 'a' and b to get the value of h as shown below

h = -b/(2a)

h = -16/(2*1)

h = -8

This is the x coordinate of the vertex.

Plug this x value into the original equation to find the corresponding y value of the vertex.

y = x^2+16x+64

y = (-8)^2 + 16(-8) + 64

y = 0

Since the y coordinate of the vertex is 0, this means k = 0.

The vertex is (h,k) = (-8, 0)

---------------------

So we found that a = 1, h = -8 and k = 0

Therefore,

f(x) = a(x-h)^2 + k

f(x) = 1(x-(-8))^2 + 0

f(x) = (x+8)^2

is the vertex form

---------------------

<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
8 0
3 years ago
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