Answer:
$50
Step-by-step explanation:
Step-by-step explanation:
- sinx+sin(x+4x) =cot2x
- sinx+sinx cos4x+cosx sin4x=cot2x
sinx+sinx cos4x=sinx (1+cos4x) =
sinx (1-1+2(cos2x)^2) =2sinx (cos2x)^2
sin4x=2sin2xcos2x
2sinx(cos2x)^2+cosx+2sin2xcos2x=cot2x
2sinxcos2x(cos2x+2(cosx)^2)=cot2x
but 2(cosx)^2=cos2x+1
2sinxcos2x(cos2x+cos2x+1)=cos2x/sin2x
(2sinxsin2x)(2cos2x+1) =1
(4cosx(sinx)^2)(2cos2x+1) =1
Answer : 3m^6-12m^5-14m^4+15m^3-12m^2-6
Considering that the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.
<h3>What are the signs of the sine and of the cosine in each quadrant?</h3>
- Quadrant 1: Both positive.
- Quadrant 2: Sine positive, cosine negative.
- Quadrant 3: Both negative.
- Quadrant 4: Sine negative, cosine positive.
Hence, since the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.
More can be learned about quadrants at brainly.com/question/28021191
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Ymm makes no sense but its pulsing so yea the answer is 52
