Given: Sound Intensity ( I ) = 
We know, the approximate threshold of human hearing is at 1kHz. In watts/m^2 it's value is
⁻¹² W/m².
So, we can say, Reference sound intensity
= 10⁻¹² W/m².
We have formula for "sound intensity level LI in dB" when entering sound intensity.
LI = 10×log (I / Io) in dB
Plugging values of I and Io in formula.
LI = 10 × log (
)
LI = 10 × log (99000000)
= 10 × 7.99564
LI = 79.96 dB.
Therefore, 79.96 dB is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2.
I think it's answer choice a
Answer:
(3,4)
Step-by-step explanation:
(6-3)(-4(--)+3)
<h2>
Answer:</h2>

<h2>Step-by-step explanation:</h2>
<u>By using external angle property</u>,
- x + x = x + 46
- 2x = x + 46
- 2x - x = 46
- x = 46 <u>Ans.</u>
Note : External angle property theorem is used when <u>sum of other two internal angle is equal to external angle</u>.