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2 years ago

Use the Distributive Property to multiply. 2(b – 7)

Mathematics

2 answers:

mr Goodwill [35]2 years ago

8 0

Answer:

2b - 14

Step-by-step explanation:

2(b – 7)

2b - 14

alexandr402 [8]2 years ago

7 0

Answer:

$2b-14$

Step-by-step explanation:

Using the distributive property, $2(b-7)$ can be written as $(2\cdot b)-(2\cdot7)$ which solved/simplified is $2b-14$

Man, it's late! Well, hope this helped you out and answered your question!

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Please help! Correct answer only!

gulaghasi [49]

Answer:

Probability ≈ 0.1071

Step-by-step explanation:

Consider steps below;

$Total Possible Outcomes - 8C5,\\\\8! / 5! ( 8 - 5 )!,\\1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 / ( 1 * 2 * 3 * 4 * 5 )( 1 * 2 * 3 ),\\\\6 * 7 * 8 / 6 = Combinations - 56,\\\\$

$Number Of Outcomes - 6C5,\\\\6! / 5! ( 6 - 5 )!,\\1 * 2 * 3 * 4 * 5 * 6 / ( 1 * 2 * 3 * 4 * 5 ) ( 1 ),\\720 / 120 * 1,\\\\Outcomes - 6$

$Conclusion ; Solution - 6 / 56 = ( About ) 0.1071\\Hope That Helps!$

Solution; Probability ≈ 0.1071

5 0

2 years ago

Expand (2x+2)^6 How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago

Please help ill give u points

Kipish [7]

Answer:

Olá, tudo bem? 

Me chamo Ana Kesia, muito prazer.

Nn entendi sua pergunta! 

Mais, mesmo assim obrigada pelos pontos.

8 0

3 years ago

When the x is slove and you have to slove for the y i got how to do it but i don't know which one am i sloving for in the equati

harina [27]

Since x=8y, subsitute 8y for x in other equation

y=6x-11
y=6(8y)-11
y=48y-11
minus y both sides
0=47y-11
add 11 to both sides
11=47y
divide both sides by 47
$\frac{11}{47}=y$
subsitute taht for y to find x

x=8y
$x=8(\frac{11}{47})$
$x=\frac{88}{47}$

$x=\frac{88}{47}$
$y=\frac{11}{47}$
in (x,y) form
(x,y)
$(\frac{88}{47},\frac{11}{47})$

3 0

3 years ago

A triangle has two sides of length 15 cm and 17 cm. Select all the values of its third side that would make it a right triangle

Natali [406]

Answer:

$\sqrt{514} cm$ , 8cm, are both options

Step-by-step explanation:

For a right triangle one can find the length of the longest side by using the Pythagorean theorem. So there are two options I can think of that if the triangle is a right triangle will work. First remember what the Pythagorean theorem is : side a^2+side b^2=hypotenuse^2

The hypotenuse is the longest side of a right triangle. So if the sides that are 15 and 17 cm are not the longest sides then the formula would be:

$15^{2} +17^2=c^2\\15^2+17^2=\sqrt{514}cm$

But if 17cm is the longest side then:

$a^2+15^2=17^2\\8^2+15^2=17^2\\a=8cm$

Hope this helps!

4 0

3 years ago

Read 2 more answers