We know that
[area of a circle ]=pi*r²
diameter=4 in
r=4 in/2-----> 2 in
so
area=pi*2²-----> area of the circle=4*pi in²
the answer is
the area, in square inches, of the circle is <span>3.14 • 2²</span>
Answer:
1.125
Step-by-step explanation:
Answer:
See proof below
Step-by-step explanation:
An equivalence relation R satisfies
- Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
- Symmetry: For all x,y, if xRy then yRx.
- Transitivity: For all x,y,z, If xRy and yRz then xRz.
Let's check these properties: Let x,y,z be bit strings of length three or more
The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.
If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.
If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.
Let x = small number
Let y = large number
Because they are consecutive even numbers,they must have a difference of 2:
y-x=2
y=2+x
Eqn 1: x+(2+x)=14
Eqn 2: x(2+x)=48
2x+2=14
2x=12
x=6
This means y must be 8
so your two numbers are 6 and 8
Answer:
36.1
Step-by-step explanation:
53.9 + 36.1 = 90
