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Bas_tet [7]
3 years ago
7

Question 1. Find h (-2)

Mathematics
2 answers:
dexar [7]3 years ago
6 0
(-2) is to 2 because -2 is the absolute value of 2
Paul [167]3 years ago
5 0

Answer:

You forgot the rest of the function, but if x is -2, then the function is represented by f(x)=-2x

If you supply more information the equation would be different.

Step-by-step explanation:

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What is the value of x: -7x = -2x + 15​
Art [367]

Answer:

-3

Step-by-step explanation:

-7x=-2x+15

collect like terms

-7x+2x=15

-5x=15

divide both sides by -5

x=15/-5

x=-3

6 0
3 years ago
Read 2 more answers
The midpoint of RS is N(-4,1). One endpoint is S(0,-7). A) what are the coordinates of R B) what is the Length of RS to the near
lora16 [44]
A) The coordinates of R is (-8,9)
B) The length of RS to the nearest tenth of a unit is 17.9
5 0
3 years ago
How do I do this its systems of equations
VLD [36.1K]
Let x the subject of the equation in x-2y=-10 this make it x=2y-10 substitute this in the first equation. 3(2y-10)-2y=-6 solve for y, y=6. substitute y in any of the original equations to get x x= 2
3 0
3 years ago
Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?
malfutka [58]
\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}

Hence, the correct options that apply are options A, D, E and F

7 0
1 year ago
How does difference of squares work?
kodGreya [7K]

Every difference of squares problem can be factored as follows: a2 – b2 = (a + b)(a – b) or (a – b)(a + b). So, all you need to do to factor these types of problems is to determine what numbers squares will produce the desired results. Step 3: Determine if the remaining factors can be factored any further.

6 0
3 years ago
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