Distance = sqrt[ (5-0)^2 + (2-0)^2]
Sqrt (5^2 + 2^2)
Sqrt(25+4)
Sqrt(29)
The equation x^2 - 36 = 5x is a quadratic equation and can be solved thus: x^2 - 36 = 5x x^2 - 5x - 36 = 0 x^2 + 4x - 9x - 36 = 0 x(x + 4) - 9(x + 4) = 0 (x - 9)(x + 4) = 0 x - 9 = 0 or x + 4 = 0 x = 9 or x = -4 Therefore, the positive solution of x^2 - 36 = 5x? is 9.
-7x^2+2x-16 i hope that helps:)
- 3 1/2 : 1 3/4 =
= -7/2 : 7/4
= -7/2 x 4/7
= -4/2
= -2
Answer:
Step-by-step explanation:
we are given two <u>coincident</u><u> points</u>
since they are coincident points
By order pair we obtain:
now we end up with a simultaneous equation as we have two variables
to figure out the simultaneous equation we can consider using <u>substitution</u><u> method</u>
to do so, make a the subject of the equation.therefore from the second equation we acquire:
now substitute:
distribute:
collect like terms:
rearrange:
by <em>Pythagorean</em><em> theorem</em> we obtain:
cancel 4 from both sides:
move right hand side expression to left hand side and change its sign:
factor out sin:
factor out 2:
group:
factor out -1:
divide both sides by -1:
by <em>Zero</em><em> product</em><em> </em><em>property</em> we acquire:
cancel 2 from the first equation and add 1 to the second equation since -1≤sinθ≤1 the first equation is false for any value of theta
divide both sides by 2:
by unit circle we get:
so when θ is 60° a is:
recall unit circle:
simplify which yields:
when θ is 300°
remember unit circle:
simplify which yields:
and we are done!
disclaimer: also refer the attachment I did it first before answering the question