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drek231 [11]
3 years ago
10

Starting with the parent function f(x)=x2, Braylin adds a positive k to f(x) to form a new function, g(x) = f(x) + k. The result

will be that his graph will _____ k units _____.
Mathematics
1 answer:
Lena [83]3 years ago
3 0
Shifted up
For example: if f(x) = x^2 + 4, the parent function has a vertex at (0,0), but the +4 shifts the graph up 4 units on the y-axis so the vertex would be (0,4)
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What is the square root of 13 ?
kipiarov [429]
<span>3.60555128 is the awnser</span>
5 0
3 years ago
1000+50-36+7×9+8÷5×2+1​
melomori [17]

Answer:

949.2

Step-by-step explanation:

To solve this equation, you must use P.E.M.D.A.S...

First, solve 7x9 and 5x2...

7x9= 63  5x2 = 10

So...

1000+50-36+63+8÷10+1

Next, solve 8÷10 and get 0.8

So...

1000+50-36+63+0.8+1

Then, solve 1000 + 50, and 36+63, and that result with 0.8 and that with 1.

So...

1050-100.8

The Solve!

949.2

Hope this helps!

<em>-kiniwih426</em>

7 0
3 years ago
Please help 20-23 it is 6th grade math and it is due October 16 please I really need help we are doing simplifying expressions a
mel-nik [20]
Hey I'm in 6th too, Simplify means to solve the prob
8 0
3 years ago
The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0
3 years ago
Given the parabola below, find the endpoints of the latus rectum. (x-2)^2=-20(y+2)
Shtirlitz [24]

Answer:

The endpoints of the latus rectum are (12, -7) and (-8, -7).

Step-by-step explanation:

A parabola with vertex at point C(x, y) = (h,k) and whose axis of symmetry is parallel to the y-axis is defined by the following formula:

(x-h)^{2} = 4\cdot p \cdot (y-k) (1)

Where:

y - Independent variable.

x - Dependent variable.

p - Distance from vertex to the focus.

h, k - Coordinates of the vertex.

The coordinates of the focus are represented by:

F(x,y) = (h, k+p) (2)

The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that h = 2, k = -2 and p = -5, then the latus rectum is between the following endpoints:

By (2):

F(x,y) = (2, -2-5)

F(x,y) = (2,-7)

By (1):

(x-2)^{2} = -20\cdot (-7+2)

(x-2)^{2} = 100

x - 2 = \pm 10

There are two solutions:

x_{1} = 2 + 10

x_{1} = 12

x_{2} = 2-10

x_{2} = -8

Hence, the endpoints of the latus rectum are (12, -7) and (-8, -7).

4 0
2 years ago
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