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fenix001 [56]
3 years ago
14

By how much is 5/8 greater than 1/4 of 1/2

Mathematics
2 answers:
lidiya [134]3 years ago
5 0
The answer is five percent
zheka24 [161]3 years ago
5 0
1/4 of 1/2 is 1/8 so 5/8 is 1/2 greater then 1/4 of 1/2.
Hope this helps.
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Abby counts 12 large boxes and 18 small boxes of pencils in the supply cabinet. Each large box contains 144 pencils . Each small
BigorU [14]

Answer:

2,160 pencils

Step-by-step explanation:

Large boxes = 12

Small boxes = 18

Each large box contains 144 pencils . Each small box contains 24 pencils

Total pencil in large boxes = Total large boxes × number of pencils per box

= 12 × 144

= 1,728 pencils

Total pencil in small boxes = Total small boxes × number of pencils per box

= 18 × 24

= 432 pencils

Estimate the total number of of pencils

Total number of pencils = total pencils in large boxes + total pencil in small boxes

= 1,728 pencils + 432 pencils

= 2,160 pencils

It is better to have an underestimate than an overestimate so that you won't disappoint your buyers when they request for a quantity of supply. If it is underestimated; you can meet demand, if it is overestimated; you can't meet demand

3 0
3 years ago
Write a story problem to go with the multiplication problem 4 x 2/3 Then, solve the problem. PLEASE HELP ASAP
Maru [420]

Answer:8/3x

Step-by-step explanation:tell if this didnt work

5 0
2 years ago
Which expression is the correct one?
Zarrin [17]
According to the logarithmic property of base change, the correpta answer is option one or the first.
 The logarithmic property of base change says that
 loga (b) = logc (b) / logc (a)
 Therefore the same property applies to this problem and the correct expression for this question is:
 logb (x) / logb (a)
3 0
3 years ago
Can someone help me please
adelina 88 [10]
Hey I think 4 B it's 5
3 0
3 years ago
Calculus 2
FinnZ [79.3K]

Answer:

See Below.

Step-by-step explanation:

We want to estimate the definite integral:

\displaystyle \int_1^47\sqrt{\ln(x)}\, dx

Using the Trapezoidal Rule, Midpoint Rule, and Simpson's Rule with six equal subdivisions.

1)

The trapezoidal rule is given by:

\displaystyle \int_{a}^bf(x)\, dx\approx\frac{\Delta x}{2}\Big(f(x_0)+2f(x_1)+...+2f(x_{n-1})+f(x_n)\Big)

Our limits of integration are from x = 1 to x = 4. With six equal subdivisions, each subdivision will measure:

\displaystyle \Delta x=\frac{4-1}{6}=\frac{1}{2}

Therefore, the trapezoidal approximation is:

\displaystyle =\frac{1/2}{2}\Big(f(1)+2f(1.5)+2f(2)+2f(2.5)+2f(3)+2f(3.5)+2f(4)\Big)

Evaluate:

\displaystyle =\frac{1}{4}(7)(\sqrt{\ln(1)}+2\sqrt{\ln(1.5)}+...+2\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx18.139337

2)

The midpoint rule is given by:

\displaystyle \int_a^bf(x)\, dx\approx\sum_{i=1}^nf\Big(\frac{x_{i-1}+x_i}{2}\Big)\Delta x

Thus:

\displaystyle =\frac{1}{2}\Big(f\Big(\frac{1+1.5}{2}\Big)+f\Big(\frac{1.5+2}{2}\Big)+...+f\Big(\frac{3+3.5}{2}\Big)+f\Big(\frac{3.5+4}{2}\Big)\Big)

Simplify:

\displaystyle =\frac{1}{2}(7)\Big(f(1.25)+f(1.75)+...+f(3.25)+f(3.75)\Big)\\\\ =\frac{1}{2}(7) (\sqrt{\ln(1.25)}+\sqrt{\ln(1.75)}+...+\sqrt{\ln(3.25)}+\sqrt{\ln(3.75)})\\\\\approx 18.767319

3)

Simpson's Rule is given by:

\displaystyle \int_a^b f(x)\, dx\approx\frac{\Delta x}{3}\Big(f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+...+4f(x_{n-1})+f(x_n)\Big)

So:

\displaystyle =\frac{1/2}{3}\Big((f(1)+4f(1.5)+2f(2)+4f(2.5)+...+4f(3.5)+f(4)\Big)

Simplify:

\displaystyle =\frac{1}{6}(7)(\sqrt{\ln(1)}+4\sqrt{\ln(1.5)}+2\sqrt{\ln(2)}+4\sqrt{\ln(2.5)}+...+4\sqrt{\ln(3.5)}+\sqrt{\ln(4)})\\\\\approx 18.423834

6 0
2 years ago
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