Answer:
0.3667 or 36.67%
Step-by-step explanation:
The probability of getting at least 1 defective hard disk among the 5 (P(X>0)) is equal to 100% minus the probability of getting none defectives (1-P(X=0)).
If 23 out of 25 hard disks are non-defective, the probability is:
The probability that there is at least 1 defective hard disk is 0.3667 or 36.67%.
This is question of probability finding using bayes theorem
It is used to calculate probability of two competing statements
now p(m) = .55
p(~m)= .45
now for basketball for male
p(b|m)=.30
and for female
p(b|~m)=.20
so by bayes theorem
p(m|b)=p(b|m)*p(m)/(p(b|m)*p(m)+p(b|~m)*p(~m))
so answer is E
(.55)(.30) / (.55)(.30) + (.45)(.20)
It is closer to ) hope i helped
