One of the legs of a right triangle has a length of 13 and the hypotenuse has a length
1 answer:
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The length and width of the rectangle is 11 in and 8 in respectively.
Step-by-step explanation:
Given,
The width of a rectangle is 3 in less than the length.
The area of each congruent right angle triangle = 44 in²
To find the length and width of the rectangle.
Formula
The area of a triangle with b base and h as height = bh
Now,
Let, the width = x and the length = x+3.
Here, for the triangle, width will be its base and length will be its height.
According to the problem,
×(x+3)×x = 44
or,
or,
or, +(11-8)x-88 = 0
or, +11x-8x-88 =0
or, x(x+11)-8(x+11) = 0
or, (x+11)(x-8) = 0
So, x = 8 ( x≠-11, the length or width could no be negative)
Hence,
Width = 8 in and length = 8+3 = 11 in
Answer:
£1443.89
Step-by-step explanation:
To start you take the £1700 and multiply it by 4% (or .04) to find how much it depreciates for the first year. For the first year the depreciation £68 so the next year it will be worth £1632 ( £1700 - 68). You do the same thing for the second year but you start with the amount its worth now (£1632) and multiply again by the 4%. The depreciation for the second year is 65.28. Now you take what it was worth at the start of the year (£1632) and subtract the depreciation for the second year (65.28) to get £1566.72. You do the same process again for the third year to end up with a value of £1504.05. Now for the 4th year you will take the value of £1504.05 and again multiply by the depreciation rate of 4% to find the last amount of depreciation which is £60.16. Take your starting value for year 4 (£1504.05) and subtract the amount of depreciation (£60.16) to get your answer of £1443.89.
