Question

Converting (x - 4)^2 + y^2 = 16 into polar form

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

(x - 4)² + y² = 16

Step 02:

polar form:

x = r cos (θ)

y = r sin (θ)

(r cos (θ) - 4 )² + (r sin (θ))² = 16

(r cos θ - 4)² + r² sin² θ = 16

r (r - 8 cos (θ)) = 0

r = 8 cos θ

The answer is:

r = 8 cos θ