Hello from MrBillDoesMath!
Answer:
x = 0, 7
Discussion:
f(g(x)) =
f ( x^2-7x) =
1/ ( x^2 - 7x)
The points NOT in the domain are those where the denominator, x^2 - 7x = 0.
x^2 - 7x = 0 => factor x from each term
x(x-7) = 0 => one or both terms must each 0
x = 0 or x =7
Thank you,
MrB
Answer:
<h2>p = (rt)/i</h2>
Step-by-step explanation:
We know that
If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment. (Intersecting Secant-Tangent Theorem)
so
ST²=RT*QT
RT=7 in
QT=23+7-----> 30 in
ST²=7*30-----> 210
ST=√210-----> 14.49 in
the answer is
RT=14.49 in
Answer:
The value of k is -11
Step-by-step explanation:
If (x+2) is a factor of x3 − 6x2 + kx + 10:
Then,
f(x)=x3 − 6x2 + kx + 10
f(-2)=0
f(-2)=(-2)³-6(-2)²+k(-2)+10=0
f(-2)= -8-6(4)-2k+10=0
f(-2)= -8-24-2k+10=0
Solve the like terms:
f(-2)=-2k-22=0
f(-2)=-2k=0+22
-2k=22
k=22/-2
k=-11
Hence the value of k is -11....
Answer:
25
Step-by-step explanation:
(6^2+4)−15
(36+4)−15
40−15
25
