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3 years ago

How do you solve equations that contain like terms

2 answers:

6 0

You add or subtract it for instance: 14x+258-52. You have to subtract 52 from 258 because of the symbol (-) in front of it. Since there is no other numbers with variables 14x is left alone. Hope this helps

igomit [66]3 years ago

5 0

You combine like terms if there are any on either side of the equal sign

Example: 4x + 3x + 5 = 8x + 2 + 3x

4x + 3x = 7x

7x + 5 = 8x + 2 + 3x

8x + 3x = 11x

7x + 5 = 11x + 2 <-- that would be the equation once all like terms are combined

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Write an equation of the line that passes through the points (0, –5) and (4, 7).

Viefleur [7K]

Y = 3 x - 5. it said my answer has to be at least 20 characters long soo.. .

7 0

3 years ago

22. Solve the system

DaniilM [7]

Equation 1) x + 6y = 2
Equation 2) 5x + 4y = 36

Multiply all of equation 1 by 5.

1) 5(x + 6y = 2)

Simplify.

1) 5x + 30y = 10
2) 5x + 4y = 36

Subtract equations from one another.

26y = -26

Divide both sides by 26.

y = -1

Plug in -1 for y in the first equation.

x + 6y = 2

x + 6(-1) = 2

Simplify.

x - 6 = 2

Add 6 to both sides.

x = 8

D : (8, -1)

~Hope I helped!~

8 0

3 years ago

Suppose that a, b \in \mathbb{Z}a,b∈Z, not both 00, and let d=\gcd(a, b)d=gcd(a,b). Bezout's theorem states that dd can be writt

lara [203]

Answer:

Step-by-step explanation:

Recall that we say that d | a if there exists an integer k for which a = dk. So, let d = gcd(a,b) and let x, y be integers. Let t = ax+by.

We know that $d | a, d | b$ so there exists integers k,m such that a = kd and b = md. Then,

$t = ax+by = (kd)x+(md)y = d(kx+my)$ . Recall that since k, x, m, y are integers, then (kx+my) is also an integer. This proves that d | t.

3 0

3 years ago

if a right triangle has one side measuring 3√2 and another side measuring 2√3, what is the length of the hypotenuse?

lina2011 [118]

Answer:

Step-by-step explanation:

Given,

Perpendicular ( p ) = 3√2

Base ( b ) = 2√3

Hypotenuse ( h ) = ?

Now, let's find the length of the hypotenuse:

Using Pythagoras theorem:

${h}^{2} = {p}^{2} + {b}^{2}$

plug the values

${h}^{2} = {(3 \sqrt{2} )}^{2} + {(2 \sqrt{3} )}^{2}$

To raise a product to a power, raise each factor to that power

${h}^{2} = 9 \times 2 + 4 \times 3$

Multiply the numbers

${h}^{2} = 18 + 12$

Add the numbers

${h }^{2} = 30$

Take the square root of both sides of the equation

$h = \sqrt{30}$

Hope this helps...

Best regards!!

6 0

3 years ago

Read 2 more answers

Pls awnser i will give brainliest pls pls

Airida [17]

Answer:

Step-by-step explanation:

Divide the smaller numbers in the table by the larger numbers (in this case diameter divided by circumference) and then compare that with the choices.

5 0

3 years ago