Answer:
-2 1/3+ -11/6 = 4.1666666666666 repeating
Step-by-step explanation:
brainlest plz
Step-by-step explanation:
You see the 90 degree angle marking at the top left so that angle is 90 degrees. However, it is bisected into two so both sections of that 90 degree angle equal 45. One triangle is equal to 180 degrees, so the triangle at the tops' missing angle is 52. I don't know if you heard of vertical angles but that angle opposite 83, because it is a vertical angle, is also 83 degrees. This is as far as I've gotten. Not sure how to solve the rest without more information
![f(x) = 10{x}^{3} - 12 {x}^{2} + 45x - 54 \\ f(x) = ( {x}^{3} - 12 {x}^{2} ) + (45x - 54) \\ f(x) = 2{x}^{2} (5x -6) + 9(5x - 6) \\ f(x) = (2{x}^{2} + 9)(5x-6)](https://tex.z-dn.net/?f=f%28x%29%20%3D%2010%7Bx%7D%5E%7B3%7D%20-%2012%20%7Bx%7D%5E%7B2%7D%20%2B%2045x%20-%2054%20%5C%5C%20f%28x%29%20%3D%20%28%20%7Bx%7D%5E%7B3%7D%20-%2012%20%7Bx%7D%5E%7B2%7D%20%29%20%2B%20%2845x%20-%2054%29%20%5C%5C%20f%28x%29%20%3D%202%7Bx%7D%5E%7B2%7D%20%285x%20-6%29%20%2B%209%285x%20-%206%29%20%5C%5C%20f%28x%29%20%3D%20%282%7Bx%7D%5E%7B2%7D%20%2B%209%29%285x-6%29)
I think this is the answer because the question you asked might have lost the 10 before
2/7 = 10/35
1/5 = 7/35
10/35 + 7/35 = 17/35.
Answer:
P(X=0)=0.732
P(X=1)=0.1962
P(X=2)=0.0526
P(X=3)=0.0141
P(X=4)=0.0038
P(X=5)=0.001
0
P(X≥6)=0.0004
Step-by-step explanation:
We want to find the probability distribution of X, where X is the number of items that must be tested before finding the first defective 10-year old widget.
This means that if X=2, the first two items are not defective and the third item is defective.
The probability of finding a defective item is p=0.732 for each trial.
Then, the probability for X=k can be written as:
![P(X=k)=(1-p)^k\cdot p=(1-0.732)^k\cdot0.732=0.278^k\cdot 0.732](https://tex.z-dn.net/?f=P%28X%3Dk%29%3D%281-p%29%5Ek%5Ccdot%20p%3D%281-0.732%29%5Ek%5Ccdot0.732%3D0.278%5Ek%5Ccdot%200.732)
Then, we can write:
![P(X=0)=0.268^0\cdot 0.732=0.732\\\\P(X=1)=0.268^1\cdot 0.732=0.1962\\\\P(X=2)=0.268^2\cdot 0.732=0.0526\\\\P(X=3)=0.268^3\cdot 0.732=0.0141\\\\P(X=4)=0.268^4\cdot 0.732=0.0038\\\\P(X=5)=0.268^5\cdot 0.732=0.001\\\\P(X\geq6)=0.0004\\\\](https://tex.z-dn.net/?f=P%28X%3D0%29%3D0.268%5E0%5Ccdot%200.732%3D0.732%5C%5C%5C%5CP%28X%3D1%29%3D0.268%5E1%5Ccdot%200.732%3D0.1962%5C%5C%5C%5CP%28X%3D2%29%3D0.268%5E2%5Ccdot%200.732%3D0.0526%5C%5C%5C%5CP%28X%3D3%29%3D0.268%5E3%5Ccdot%200.732%3D0.0141%5C%5C%5C%5CP%28X%3D4%29%3D0.268%5E4%5Ccdot%200.732%3D0.0038%5C%5C%5C%5CP%28X%3D5%29%3D0.268%5E5%5Ccdot%200.732%3D0.001%5C%5C%5C%5CP%28X%5Cgeq6%29%3D0.0004%5C%5C%5C%5C)