Answer:
ΔT = ΔT0 e^-K T
As I understand Newton's Law of Cooling
ΔT at any time is the difference between the temperature and the surroundings
Originally ΔT0 = 95 - 22 difference between 95 and room temperature
65 - 22 = 33 = 73 e^-KT where t is time to cool to 65 deg
ln (33/73) = -KT K = .794 / 5 = .159 where 5 is time to cool to 65 deg
40 - 22 = 73 e^-.159 T where t is time to cool to 40 deg
18 = 73 e^-.159 T
ln (18 / 73) = -.159 T
T = 8.8 min
It would take 8.8 min for the object to cool to 40 deg C
Suppose the object cooled from 95 to 90 deg, then
ln 68 / 73 = -.159 T and T = .45 min
ANSWER
EXPLANATION
From the given information, Elena chooses a number from 1 to 10.
The sample space is
S={1,2,3,4,5,6,7,8,9,10}
n(S)=10
The numbers greater than 5 are:
E={6,7,8,9,10}
n(E)=5
The probability that, she chooses a number greater than 5 is:
Substitute the values,
Answer:
a) 1/8 b) 1/6
Step-by-step explanation:
b) 6/36 = 1/6
a) 1/2 x 1/2 x 1/2 = 1/8
