Will Mark Brainlest helppp plss

Doctors can approximate the Body Surface Area (BSA) of an adult (in square meters) using the BSA index: B⁢S⁢A=H⋅W3600 , where H

Anettt [7]

<span>75 kilograms The equation given for BSA doesn't look correct, perhaps due to formatting issues involving a simple copy and paste without any proofreading afterwards. Doing a quick google search gives the Mosteller formula for BSA which is: BSA = sqrt(W*H/3600) This formula is quite likely the original target of the copy and paste since it has all of the correct values and it's likely that the square root symbol wasn't properly pasted, nor the horizontal bar indicating division. So I'll use the Mosteller formula in solving this problem: First, solve for W, then substitute the known values and calculate: BSA = sqrt(W*H/3600) BSA^2 = W*H/3600 3600*BSA^2 = W*H 3600*BSA^2/H = W 3600*1.96^2/185 = W 3600*3.8416/185 = W 74.755 = W So the weight of the adult is 75 kilograms. If the incorrectly copied equation of Bâ˘Sâ˘A=Hâ‹…W3600 were to be used and if the missing operator between the W and the 3600 were a divide symbol, the calculated value would be 38 kg, which is rather light for someone 185 cm tall since the low end of healthy is 65 kg. And if the missing operator between the W and 3600 was a multiply, then the calculated weight would be 3 micrograms which is way too small for a human being, no matter how starved. However, the value calculated using the Mosteller formula would represent a BMI of 22 which is about average for a normal healthy adult.</span>

8 0

3 years ago

80.8=8(m+2.8) what is this answer

Aleonysh [2.5K]

The answer is 7.3, If you use the order of operations, When you divide 58.4 by 8 you get 7.3

8 0

3 years ago

Solve this inequality: 3p – 16 < 20.

mamaluj [8]

P<12 would be the answer to this question.

3 0

2 years ago

Income Suppose income from an endowment is generated at the annual rate of $42,000 per year. Find the capital value of this endo

Mrac [35]

Answer:

Capital value after 1 year will be equal to $45150

Step-by-step explanation:

We have given principal amount P = $42000

Rate of interest r = 7.5 %

Time t = 1 year

Capital value is given by $A=P(1+\frac{r}{100})^n$

So $A=42000\times (1+\frac{7.5}{100})^1$

$A=42000\times 1.075=45150$

So capital value after 1 year will be equal to $45150

4 0

3 years ago

Please help?

Mazyrski [523]

Answer:

$23\sqrt{3}\ un^2$

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

$A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\$

2. Note that

$A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2$

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

$A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2$

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

7 0

3 years ago

Will Mark Brainlest helppp plss​

Will Mark Brainlest helppp plss