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zhenek [66]
4 years ago
14

20. Simplify: 4×^3√3x+5 ^3√10x

Mathematics
1 answer:
Elenna [48]4 years ago
7 0
5∛(10)∛(x)+4∛(3)<span>∛(x)
But in the comments you wrote the choices and none of them match with the answer i got. so i would say its B</span>
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A fence on a hill uses vertical posts L and M to hold parallel rails N and P. ∠10 and ∠14 are alternate interior angles. What is
kherson [118]
The answer is B. Thank you:$))
7 0
3 years ago
Find the percent of change. Original: 80, new: 64
kari74 [83]

80 - 64 = 16

16/80 = 0.2 = 20%

Answer: 20% decreased.

4 0
3 years ago
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Tyler used 114 gallons of paint to paint 47 of a fence. How many gallons will it take to paint the whole fence?
lara31 [8.8K]

Answer: It will take 199.5 gallons to paint the whole fence.

Step-by-step explanation:

Given:  Paint required to paint \dfrac47of fence = 114 gallons

Then , paint required to paint whole fence = 114\div\dfrac47

i.e. paint required to paint whole fence = 114\times\dfrac{7}{4}

i.e.  Paint required to paint whole fence= 199.5 gallons

Hence, it will take 199.5 gallons to paint the whole fence.

3 0
3 years ago
Find the absolute value of the complex number 5 - 4i.<br> a. -6.4<br> c. 6.04<br> b.6<br> d. 6.4
Tanya [424]
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6 0
4 years ago
According to Boyle's Law, if the temperature of a confined gas is held fixed, then the product of the pressure P and the volume
Bad White [126]

If <em>PV</em> = 800, then <em>P</em> can be written as a function of <em>V</em>,

<em>P(V)</em> = 800 / <em>V</em>

(a) The average rate of change of <em>P</em> as <em>V</em> increases from 200 to 250 in³ is then

(<em>P</em> (250) - <em>P</em> (200)) / (250 in³ - 200 in³) = (3.2 lb/in² - 4lb/in²) / (50 in³)

... = -0.016 (lb/in²)/in³

(Or -0.016 lb/in⁵, but I figure writing the rate as (units of pressure) per (unit volume) makes more sense.)

(b) We can also write <em>V</em> as a function of <em>P</em> :

<em>V(P)</em> = 800 / <em>P</em>

Take the derivative:

<em>V'(P)</em> = - 800 / <em>P</em>²

which immediately demonstrates that <em>V'(P)</em> ∝ 1 / <em>P</em>², as required. (The fish-looking symbol, ∝, means "is proportional to".)

If differentiating is supposed to be more involved, you can use the limit definition:

V'(P)=\displaystyle\lim_{h\to0}\frac{V(P+h)-V(P)}h

V'(P)=\displaystyle\lim_{h\to0}\frac{\frac{800}{P+h}-\frac{800}P}h

V'(P)=\displaystyle\lim_{h\to0}\frac{\frac{800P-800(P+h)}{P(P+h)}}h

V'(P)=\displaystyle800\lim_{h\to0}\frac{-\frac h{P(P+h)}}h

V'(P)=\displaystyle-800\lim_{h\to0}\frac1{P(P+h)}=-\dfrac{800}{P^2}

7 0
3 years ago
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