Answer:
G(x+2) = 7x^2 + 33x + 30
Step-by-step explanation:
So in the G(x) function, to find G(x+2), we just simply plug in the value of x+2 into the function and the result is what is wanted. SO:
G(x+2) = 7(x+2)^2 + 5(x+2) -8 , which is 7x^2 +33x +30 after SIMP - lifying (see what I did there ;)
Hope i helped, please make this brainly. :)
They are made by 1. 4 is made by 2, 8 is made by 2 and 4, 6 is made by 2 and 3.
I don’t know the depth but I can tell you that you need to multiply everything using the formula v=l*w*h. So v=3.5*0.5*x
Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:

Rewrite the integrand:

The integral is then
