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DiKsa [7]
3 years ago
9

The cost of fertilizing a lawn is​ $0.25 per square foot. find the cost to fertilize the triangular lawn whose base is left pare

nthesis 14 plus startroot 17 endroot right parenthesis feet and altitude is startroot 68 endroot feet.
Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0
To Calculate the cost of <span>The cost of fertilizing, we need to Calculate first the Area of the Triangle.

</span>the Area of the Triangle = 1/2 x base x altitude = 1/2 x (14+√17) x 68 = 524.08 <span>square foot

</span>The cost of fertilizing = the cost of the square foot x the total area = 0.25x524.08 = 131 <span>$</span>
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Which of the following shows the true solution to the logarithmic equation 3 log Subscript 2 Baseline (2 x) = 3
VARVARA [1.3K]

Answer:

x = 1

Step-by-step explanation:

We have to solve the given logarithmic equation of variable x.

The equation is 3\log _{2} (2x) = 3

⇒ \log_{2} (2x)^{3} = 3  

{Since, we know the logarithmic property, a \log b = \log b^{a}}

⇒ \log_{2} (2x)^{3} = 3\log_{2}2 = \log_{2} 2^{3}

{Since we know that \log_{a} a = 1}

Now cancelling log from both sides we get,  

(2x)^{3} = 2^{3}

⇒ x^{3} = 1

⇒ x = 1 (Answer)

7 0
3 years ago
Jean adds 35 and 9 how can she solve using only equations to model her thinking ?explain
alisha [4.7K]
35+9
It shows that she is adding so add the two numbers together
7 0
4 years ago
URGENT PLZZZ HELP
viktelen [127]

The area of the shaded portion = 100.48 cm²

Solution:

Radius of the inner circle = 2 cm

Radius of the outer circle = 6 cm

Area of the inner circle = \pi r^2

                                      =3.14 \times 2^2

Area of the inner circle = 12.56 cm²

Area of the outer circle = \pi R^2

                                      =3.14 \times 6^2

Area of the outer circle = 113.04 cm²

Area of the shaded portion = Area of the outer circle – Area of the inner circle

                                      = 113.04 cm² – 12.56 cm²

                                      = 100.48 cm²

Hence the area of the shaded portion = 100.48 cm²

4 0
3 years ago
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sergey [27]

It is given in the question that,

Julio is paid 1.2 times his normal hourly rate for each hour he works over 29 hours in a week. Last week he worked 34 hours and earned $434.00.

And Julio's normal hour rate is r.

So the earning equation is

434 = 29r + (34-29)(1.2r)

434 = 29r + 5(1.2r)&#10;\\&#10;434 = 29r + 6r&#10;\\&#10;434 = 35 r&#10;\\&#10;r = $12.40

This is reasonable, because working 34 hours with a rate of $12 per hour is

34*12 = 34(10+2) = 340 +68 = $408

And $408 is close to $434.

4 0
3 years ago
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kumpel [21]

Answer:

1000 in base 14

Step-by-step explanation:

DDD + 1 = 1000 in base 14

6 0
2 years ago
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