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3 years ago

How many lines of symmetry does the figure have? I think it's 6, but I could be wrong

Mathematics

2 answers:

Gnesinka [82]3 years ago

3 0

Answer: You are right it is 6

Step-by-step Explanation

Every circle counts as one so it is 6

BTW how do you make the picture appear

Gekata [30.6K]3 years ago

3 0

From the looks of it, i think you’re right.

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Please solve my difficult question fast

kicyunya [14]

The 3 angles form the straight line AB. A straight line equals 180 degrees.

The 3 angles when added together need to equal 180:

2x + 65 + (x + 65) = 180

Simplify by combining like terms:

3x + 130 = 180

Subtract 130 from both sides

3x = 50

Divide both sides by 3

X = 50/3

X = 16 2/3 (16.66667 as a repeating decimal)

Now you have x if you need to solve all the angles replace x with its value and sole:

2x = 2(16 2/3) = 33 1/3

X + 65 = 16 2/3 + 65 = 81 2/3

7 0

3 years ago

Read 2 more answers

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say E occurring is:

$P (E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, n = 20.

Number of defective electric toothbrushes is, x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

${20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

${3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$=\frac{3}{190}\\$

$=0.01579\\\approx0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0

3 years ago

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alex41 [277]

Yes, and what is the problem?

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3 years ago

The rate at which an assembly line workers efficiency E (expressed as a percent) changes with respect to time t is given by E'(t

zavuch27 [327]

By the fundamental theorem of calculus,

$E(t)=E(1)+\displaystyle\int_1^t E'(u)\,\mathrm du$

So we have

$E(t)=92+\displaystyle\int_1^t(75-6u)\,\mathrm du$

$E(t)=92+(75u-3u^2)\bigg|_1^t$

$E(t)=20 + 75 t - 3 t^2$

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3 years ago

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ruslelena [56]

A. 12pi meters.

Circumference = pi x diameter (pi x 12 = 12pi)
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3 years ago