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Sedbober [7]
3 years ago
14

Which of these graphs do not represent constant rates of change? Check all that apply.

Mathematics
2 answers:
avanturin [10]3 years ago
5 0

Answer:

A,D

Step-by-step explanation:

I'm taking the test

Arada [10]3 years ago
4 0

Answer:

the answer is A and D

Step-by-step explanation:

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Elimination_4x_2y=14<br> _10x+7y=_24
Gnesinka [82]

Answer:

The answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

Step-by-step explanation:

Given:

-4x-2y=14

-10x+7y=-24

Now, to solve it by elimination:

-4x-2y=14   ......(1)

-10x+7y=-24 ......(2)

So, we multiply the equation (1) by 7 we get:

-28x-14y=98

And, we multiply the equation (2) by 2 we get:

-20x+14y=-48

Now, adding both the new equations:

-28x-14y+(-20x+14y)=98+(-48)

-28x-14y-20x+14y=98-48

-28x-20x-14y+14y=50

-8x=50

<em>Dividing both the sides by -8 we get:</em>

x=-\frac{50}{8}

Now, putting the value of x in equation (1):

-4x-2y=14

-4(-\frac{50}{8})-2y=14

\frac{200}{8} -2y=14

25-2y=14

<em>Subtracting both sides by 25 we get:</em>

-2y=-11

<em>Dividing both sides by -2 we get:</em>

y=\frac{11}{2}

Therefore, the answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

5 0
3 years ago
Question is on the photo pls help
Bond [772]

Answer:

d)-8

Step-by-step explanation:

  1. -6s-¹t²
  2. -6(3)-¹(-2)²
  3. -6(⅓)(4)
  4. -8
4 0
3 years ago
Let F(x,y)=1+sqrt(4-y^2). . (a) Evaluate F(3,1). (b) Find and sketch the domain of F. (c) Find the range of F
charle [14.2K]
The goal of this function is to get  a positive value under the square root sign so that the value would not be invalid. Evaluating F(3,1), the value is 1 + <span>sqrt(4-1^2) or equal to 1 + sqrt of 3.</span> In this case, the domain would be x equal to any numbers and the range equal to numbers from -2 ≤ y ≤ 2. 
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3 years ago
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For the quadratic equation 3x^2−7x+4=0, enter the correct values of a, b, and c.
Alex73 [517]

Answer:

since 3x^2-7x+4=0 is in the form ax^2+bx+c=0, a=3, b=-7, c=4

6 0
3 years ago
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