We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.
<h3>
How to get the slope of the line that passes through the points (9, 1) and (10, - 1)?</h3>
A linear equation has the general form:
y = a*x + b
Where a is the slope of the line, and b is the y-intercept.
There is a simple equation to get the slope of a point if we know two points. For a line that passes through ( a, b) and (c, d), the equation for the slope is:
a = (d - b)/(c - a)
In this case we know that our line passes through (9, 1) and (10, -1), then using the above equation, we can see that the slope is:
a = (-1 - 1)/(10 - 9) = -2
We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.
If you want to learn more about linear equations:
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Answer:X^2-7X=57/4
Step-by-step explanation:
Y=X^2-7X+57/4
X^2-7X=57/4
Answer:

Step-by-step explanation:
The conjugate of a radical expression is obtained by changing the sign of the middle term.
The conjugate of
is simply 
Therefore, to obtain the conjugate of the given expression we simply shall be changing the negative sign to positive;
The conjugate of
is simply;

The volume of one die is the edge to the power of 3:

The total volume is five times the above volume:

Answer:
Answer:
x = 3
Step-by-step explanation:
Given the linear equation :
1/4(x-5)+4=1/3(2x+7)-5/6
(x-5)/4 + 4 = (2x+7)/3 - 5/6
Take the lcm and sum
(x-5+16)/4 = (4x+14-5)/6
(x+11)/4 = (4x+9)/6
Cross multiply
6(x+11) = 4(4x+9)
6x + 66 = 16x + 36
Collect like terms
6x - 16x = 36 - 66
-10x = - 30
x = 30/10
x = 3