5 is your answer . i hate permutations
This looks super duper hard wish I can solve it out
Answer: 10√3 / 3
Step-by-step explanation:
cos 30 = 5 / x
x = 5 / cos 30
= 5 / √3 / 2
= 10 √3
= 10√3 / 3
Answer:
![\sqrt[5]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B4%7D)
+ ![\sqrt[10]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7B3%7D)
Step-by-step explanation:
We sure can write 2^2/5+ 3^1/10 as 
// use the ![a^{\frac{m}{n} } =\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
to transform the expression
Convert 
to ![\sqrt[5]{2^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E%7B2%7D%20%7D)
= (here a = 2, n = 5, m = 2)
Then convert 
to ![\sqrt[10]{3^{1} }](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7B3%5E%7B1%7D%20%7D)
= (here a = 3, n = 10, m = 1)
Now we get = + . This is the simplified form, which is the answer.
Remember, |n|≥0 for all real numbers n
so
-|x|=0
times -1
|x|=0
true, x=0, has a solution
|x|=-15
false, can't have negative absolute value
-|x|=12
|x|=-12
false, no negative absolute value
-|-x|=9
|-x|=-9
false, no negative absolute value
-|-x|=-2
|-x|=2
x=2 or -2
true, has solutions
the ones that have no solutions are
|x|=-15
-|x|=12
-|-x|=9
