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LenKa [72]
3 years ago
12

State whether each of the following sets of data are possible for the matrix equation AX = B. If possible, describe the solution

set. That is, tell whether there exists a unique solution, no solution or infinitely many solutions. Here, [A|B] denotes the augmented matrix.
(A) A is a 5 × 6 matrix, rank(A) = 4 and rank[AIB] = 4.
(B) A is a 3 x 4 matrix, rank (A) = 3 and rank [AIB] = 2.
(C) A is a 4 × 2 matrix, rank (A) = 4 and rank[A|B| = 4
(D) A is a 5 × 5 matrix, rank (A) = 4 and rank [A|B] = 5.
(E) A is a 4 × 2 matrix, rank (A) = 2 and rank [A|B] = 2.
Mathematics
1 answer:
nasty-shy [4]3 years ago
3 0

Answer:

(A) Possible, the system will always have infinite solutions.

(B) Impossible.

(C) Impossible.

(D) Possible, there is no solutions.

(E) Possible, unique solution.

Step-by-step explanation:

(A) It possible, for example consider

\left[\begin{array}{cccccc|c}1&0&0& 0 & 0& 0& 0\\0&1&0&0 & 0 & 0 & 0\\0&0&1&0 & 0 & 0& 0\\0&0&0&1 & 0 & 0& 0\\0&0&0&0& 0 & 0& 0\end{array}\right]

in this case, the system will always have infinite solutions (there at most two variable that could take any valour).

(B) It is impossible because rank[A|B] \ge 3.

(C) It is impossible because rank(A) \le 2.

(D) It is possible, for example consider

\left[\begin{array}{ccccc|c}1&0&0& 0 & 0& 0\\0&1&0&0 & 0 & 0 \\0&0&1&0 & 0 & 0\\0&0&0&1 & 0 & 0\\0&0&0&0& 0 & 1\end{array}\right]

but in this case there is no solutions.

(E) It is possible, for instance, consider

\left[\begin{array}{cc|c}1&0&0\\0&1&0\\0&0&0\\0&0&0\end{array}\right]

Now, if this is the case there exists a unique solution.

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Step-by-step explanation:

To draw the graph, follow these steps:

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  3. Find the boundary given.

The three inequalities given form a triangle.

The first equation, y ≤ 2x + 5, has a y-intercept at (0, 5) and a point at (-2, 1).

The second equation, y < -3x + 10, has points at (3, 1) and (2, 4).

Use two points to draw the lines.

After the lines are drawn, determine which side of the line the inequality works on. You can do this by testing points that are not on the line.

I will test each inequality using (0, 1):

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<em>This is correct</em>, so the inequality for y ≤ 2x + 5 will be shaded towards (0, 1).

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<em>This is correct,</em> so the inequality for y < -3x + 10 will be shaded towards (0, 1).

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Answer:

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