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earnstyle [38]
3 years ago
11

For what value of a is -√a < - 1/-√a 2 ⅓ 1 0

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

it's 1 because it subtract the sides

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Move options to the blanks to define the transformations that can be done on C1 to show that it is similar to circle C2.
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Circle C1 can be dilated at its center by a scale factor of 1/2. Then the image can be translated left 4 and down 6. This will map circle C1 onto circle C2 and prove they are similar.

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Can u simplify 8/50 to a simpler fraction?
Licemer1 [7]
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3 years ago
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Help please
tester [92]

Answer:

64y² - 81

Step-by-step explanation:

(8y +9)(8y - 9)

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The graph depicts the growth and costs using of line segment use the midpoint formula to approximate the cost during the year 19
marysya [2.9K]

Answer:

The approximate cost during the year 1987 was $7,533

Step-by-step explanation:

The complete question in the attached figure

we have

y -----> is the cost in dollars

x -----> is the year

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(1983,5,047) and (1991, 10,019)

To determine the cost in the year 1987, find out the midpoint between the two given points

The formula to calculate the midpoint between two points is equal to

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

substitute the values

M=(\frac{1983+1991}{2},\frac{5,047+10,019}{2})

M=(1987,7,533)

therefore

The approximate cost during the year 1987 was $7,533

7 0
3 years ago
Solve solve the following equations 2x (x minus 5) close + 3(x-2)=8+7(x-4)​
stiv31 [10]

Step-by-step explanation:

<em>2</em><em>x</em><em>(</em><em>x-5</em><em>)</em><em>+</em><em>3</em><em>(</em><em>x-2</em><em>)</em><em>=</em><em>8</em><em>+</em><em>7</em><em>(</em><em>x-4</em><em>)</em>

<em>2</em><em>x</em><em>²</em><em>-10x</em><em>+</em><em>3</em><em>x</em><em>-</em><em>6</em><em>=</em><em>8</em><em>+</em><em>7</em><em>x</em><em>-</em><em>2</em><em>8</em><em>(</em><em>Group</em><em> </em><em>like</em><em> </em><em>terms</em><em>)</em>

<em>2</em><em>x</em><em>²</em><em>-</em><em>1</em><em>0</em><em>x</em><em>+</em><em>3</em><em>x</em><em>-</em><em>7</em><em>x</em><em>=</em><em>8</em><em>-</em><em>2</em><em>8</em><em>+</em><em>6</em>

<em>2</em><em>x</em><em>²</em><em>-</em><em>7</em><em>x</em><em>-</em><em>7</em><em>x</em><em>=</em><em>-</em><em>2</em><em>0</em><em>+</em><em>6</em>

<em>2</em><em>x</em><em>²</em><em>-</em><em>1</em><em>4</em><em>x</em><em>=</em><em>-</em><em>1</em><em>4</em><em>(</em><em>Divi</em><em>de</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em>1</em><em>4</em><em>)</em>

2x²<em>-</em><em>x</em><em>=</em><em>1</em>

<em>2</em><em>x</em><em>=</em><em>1</em>

<em>x</em><em>=</em><em>½</em>

<em>Hope</em><em> </em><em>you </em><em>get</em><em> </em><em>it</em><em> </em><em>please</em><em> </em><em>someone</em><em> </em><em>shou</em><em>ld</em><em> </em><em>verify</em><em>.</em><em>.</em><em>.</em><em>.</em>

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