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12345 [234]
3 years ago
6

Jason collects baseball cards. He has 280 cards. Of these, 40% feature players from the New York Yankees baseball team. How many

baseball cards does Jason have that feature players from teams other than the New York Yankees?
Mathematics
1 answer:
andre [41]3 years ago
3 0
You'd need to start by finding what 40% of 280 is. To do this, you turn 40% into a decimal which is .40 . Multiply .40 x 280 which is 112. Then subtract that answer from 280 which is 168 baseball cards. Hope this helped :)
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<span>3(2t + 5) = 5t + 25
6t + 15 = 5t + 25
6t - 5t = 25 - 15
t = 10</span>
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ch4aika [34]

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Step-by-step explanation:

∠ACB and ∠ECD are vertical angles, so ∠ACB = ∠ECD.

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△ABC and △EDC are similar because they have the same angles.

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3 years ago
Octagon ABCDEFGH and its dilation, octagon A'B'C'D'E'F'G'H', are shown on the coordinate plane below:
Vaselesa [24]

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Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

Dilation is the enlargement or reduction of the size of an object. If a figure with point A(x, y) is dilated by a scale factor of k about the center of the origin, the new point would be at (kx, ky). If k < 1 it is a reduction and if k > 1 it is an enlargement.

The octagon ABCDEFGH has vertices at A(3, 1), B(3, -1), C(1, -3), D(1, -3), E(-3, -1), F(-3, 1), G(-1,3) and H(1, 3)

Octagon ABCDEFGH is then dilated about the origin to form octagon A'B'C'D'E'F'G'H' with vertices at A'(6, 2), B'(6, -2), C'(2, -6), D'(2, -6), E'(-6, -2), F'(-6, 2), G'(-2,6) and H'(2, 6)

A = (3, 1) and A' = (6, 2) = [2(3), 2(1)]

Therefore octagon ABCDEFGH was dilated by a scale factor of 2 to form octagon A'B'C'D'E'F'G'H'

6 0
3 years ago
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dsp73

Answer:

a) \log 52

b) \log_57

Step-by-step explanation:

Use logarithm properties:

\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}

Then

a) \log 13+\log 4=\log 13\cdot 4=\log 52

b) \log_514-\log _52=\log _5\dfrac{14}{2}=\log _57

7 0
3 years ago
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