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vova2212 [387]
4 years ago
15

Find the area of a circle with a circumference of 31.42 centimeters.

Mathematics
2 answers:
denis-greek [22]4 years ago
8 0

c = 2(pi)r = 31.42cm

2(3.14)r = 31.42cm

6.28r = 31.42cm

r = 31.42cm / 6.28

r = 5cm

A = (pi)r^2

= (3.14) (5)^2

5x5 = 25cm

25x3.14= 78.5cm

the area equals 78.5cm

andrew-mc [135]4 years ago
4 0

Answer:

A≈78.56cm²

Hope this helps you out!

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Wittaler [7]

Answer:

d. y-3 = f(x)

Step-by-step explanation:

we don't know what f(x) is. but we can see that the red line is 3 units above the black line. so we are adding 3 to whatever f(x) is. so the red line should have the equation

y = f(x) +3

subtract 3 from both sides

y-3 = f(x)

4 0
4 years ago
Que es la recta numerica
Gelneren [198K]

Answer:

Un ejemplo de una recta numérica es lo que un estudiante de matemáticas puede usar para encontrar la respuesta a las preguntas de suma y resta. Una línea recta, teóricamente que se extiende hasta el infinito en direcciones tanto positivas como negativas desde cero, que muestra el orden relativo de los números reales.

explanation:

what is the number line

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8 0
3 years ago
Find the equation of a line that is perpendicular to 4x+6y=1 that has a greater y intercept compared to 2x+3y=18
Marina86 [1]

Answer:

4y = 6x + 40

Step-by-step explanation:

The general equation of a straight line is y = mx + b

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let us write both equations in this form;

we have this as;

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y = -4x/6 + 1/6

and;

2x + 3y = 18

3y = -2x + 18

y = -2x/3 + 6

So firstly we want to find an equation that is perpendicular to the first

When two lines are perpendicular, their slopes has a product of -1

The slope of the first line is -4/6

let the slope of the line we want be m

As per they are perpendicular;

-4/6 * m = -1

-4m/6 = -1

-4m = -6

m = 6/4

So now, we want the y-intercept greater than that of the second equation which is a y-intercept of 6

we can choose 10

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y = 6x/4 + 10

multiply through by 4

4y = 6x + 40

7 0
3 years ago
Cube shape is very difficult
seropon [69]

Answer:

A, C, and D are right.

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Step-by-step explanation:

Hope this helped.

A brainliest is always appreciated.

3 0
3 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
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