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3 years ago

Find the equation of a line that is perpendicular to 4x+6y=1 that has a greater y intercept compared to 2x+3y=18

Mathematics

1 answer:

Marina86 [1]3 years ago

7 0

Answer:

4y = 6x + 40

Step-by-step explanation:

The general equation of a straight line is y = mx + b

m is the slope and b is the y-intercept

let us write both equations in this form;

we have this as;

6y = -4x + 1

y = -4x/6 + 1/6

and;

2x + 3y = 18

3y = -2x + 18

y = -2x/3 + 6

So firstly we want to find an equation that is perpendicular to the first

When two lines are perpendicular, their slopes has a product of -1

The slope of the first line is -4/6

let the slope of the line we want be m

As per they are perpendicular;

-4/6 * m = -1

-4m/6 = -1

-4m = -6

m = 6/4

So now, we want the y-intercept greater than that of the second equation which is a y-intercept of 6

we can choose 10

and we have the equation as:

y = 6x/4 + 10

multiply through by 4

4y = 6x + 40

Read more on complex inequality;

brainly.com/question/24761100

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5 0

1 year ago

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

7 0

3 years ago

I’ll mark brainliest

natta225 [31]

A:C

Step-by-step explanation:

6 0

3 years ago

A boat is heading towards a lighthouse, whose beacon-light is 136 feet above the

alexandr1967 [171]

The distance between the points A to B is 899.9 feet. After rounding off the nearest integer we get 900 feet as the final answer.

Given we know that CD is perpendicular to AD.

The distance between CD is 139 feet.

As from points A the boat's crew measure the angle of elevation to the beacon as 6°

therefore, m∠A = 6°

Another time the angle of elevation is measured from point B which is 19°.

therefore, m∠DBC = 19°

tan 19° = CD/BD

BD = CD/tan19°

BD = 136/tan 19°

now for tan 6° = CD/AD (tangent is opposite over adjacent)

AD = CD/tan 6°

AD = 136/tan 6°

AB = AD ₋ BD

AB = 136/tan 6° ₋ 136/tan 19°

AB = 1295.2 ₋ 395.3

AB = 900 feet

hence the distance from point A to B is 900 feet.

Learn more about Heights and distances here:

brainly.com/question/2004882

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5 0

2 years ago

What are the coordinates of (-3,4) when it is reflected over the y-axis.

AysviL [449]

Answer:

D. (4,3)

Step-by-step explanation:

(-3,4)

Reflection in the y-axis:

Same y, -ve x

(3,4)

Reflection in y = x

(x,y) goes to (y,x)

(3,4) goes to (4,3)

3 0

3 years ago