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julsineya [31]
3 years ago
6

Given that the series kcoskt kº +2 k=1 converges, suppose that the 3rd partial sum of the series is used to estimate the sum of

the series. Which of the following values gives the best bound on the remainder (error) for this approximation?
a. 1/2
b. -3 / 29
c. 2/ 33
d. 1/5
Mathematics
1 answer:
3241004551 [841]3 years ago
5 0

Answer:

c

Step-by-step explanation:

Given that:

\sum \limits ^{\infty}_{k=1} \dfrac{kcos (k\pi)}{k^3+2}

since cos (kπ) = -1^k

Then, the  series can be expressed as:

\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^kk)}{k^3+2}

In the sum of an alternating series, the best bound on the remainder for the approximation is related to its (n+1)^{th term.

∴

\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^{(3+1)}(3+1))}{(3+1)^3+2}

\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^{(4)}(4))}{(4)^3+2}

= \dfrac{4}{64+2}

=\dfrac{2}{33}

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