Answer/Explanation:
Given an estimated beetle population of 11,500, of which it is estimated to increase approximately by 5% each year, we can calculate the estimated population for each year as follows:
<u>Year Calculation Est. Population</u>
1st yr (current yr) 11,500
2nd yr 11,500*105% 12,075
3rd yr 12,075*105% 12,679
4th yr 12,679*105% 13,313
5th yr 13,313*105% 13,979
<u>6th yr 13,979*105% </u><u>14,678</u>
The above is how the table would like showing the estimated population for each year.
When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.
The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.
The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.
We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.
Parents: BB x Bb
Gametes: B, B, and B, b
Offspring: BB, BB, Bb, Bb
The genotypic ratio = 1:1
The phenotypic ratio = 1:0
Genotype probabilities:
P(BB) = 2/4 = 0.5 or 50%
P(Bb) = 2/4 = 0.5 or 50%
Learn more about genotype here:
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I think its a density dependent limited factor
Answer:
Pinocytosis is the mechanism by which living cells consume liquid droplets. Endocytosis is the general mechanism by which cells ingest foreign substances and collect them in special membrane-bound vesicles within the cell. Pinocytosis is one form of endocytosis.
