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Nezavi [6.7K]
3 years ago
10

A recipe calls for 2 tsp of butter. Melinda wants to make 40% more servings than the recipe makes.

Mathematics
1 answer:
olga_2 [115]3 years ago
3 0
Given:
recipe: 2 tsp of butter
Melinda wants to make 40% more servings than the recipe.

2 tsp is equal to 100%
additional of 40% makes it 100% + 40% = 140%

140% * 2 tsp = 2.8 tsp.

The expression that shows the number of teaspoons needed is:
D. 1.4 x 2
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A set of raw paired sample data is given below. Convert this raw data into paired ranks, and calculate the value of the rs test
SOVA2 [1]

here is the data set for the complete question

x: 18 21 19 21 20 21

y; 2 14 5 6 18 18

Answer:

B. 0.652

Step-by-step explanation:

x   y   rank of x     rank of y   d         d²

18   2     1                1               0          0

21   14    4                4             0          0

19    5     2               2             0          0

21    6     4               3            1            1

20    18    3             5.5         -2.5      6.25

21     18    4             5.5          -1.5       2.25

∑d² = 8.5

rs = 1 - 6[∑di² + ∑m(m²-1)]/n(n²-1)

= 1 - 6[8.5 +{3(3²-10/12 + 2(2² - 1)/12}]/6(6²-1)

= 1 - 0.348

= 0.652

therefore option b is the right answer.

5 0
3 years ago
How to evaluate the expression 0.3(3-0.5)
scoray [572]
0.3(3 - 0.5)
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3 0
3 years ago
Help pls also show work if needed!!
kifflom [539]

Answer:

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Step-by-step explanation:

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3 years ago
An object is launched with a velocity at 64 feet per second from a platform 30 feet high. the function H(t)= -16t2+64t+30 repres
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To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.

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Now find the critical numbers:

-32t + 64 = 0

-32t = -64

t = 2 seconds

Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):

H'(1) = 32

H'(3) = -32

As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.

To find the height, plug t=2 into H(t):

H(2) = -16(2)^2 +64(2) + 30 = 94

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Which points lies on the line described by the equation? y+4=(x-3)
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Hello : 
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