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kondor19780726 [428]
3 years ago
6

2/7(x+4)=−6 help x=−35 x=−25 x = 25 x =35

Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer:

x= -25

Step-by-step explanation:

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I just need a starter to help me on this. Thanks:)
zhenek [66]
I could help. So mark days as the X value and hours as the Y value
so for the days(x) start with 1 and put in the hours(y) 24 the for the second column in the days(x) box put 2 and in the hours(y) put 48 then continue to at 12 to the hours(y) and 1 to the days(x)
5 0
4 years ago
Two number cubes are rolled for two separate events: 
MatroZZZ [7]

Let us first make the sample space for the event A. The Sample Space will be:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

As can be clearly seen the Sample Space for the event A has 30 elements in it.

Now, it is given in the question that the event A has already occurred and we need to find the probability of the event B occurring <u><em>given that the event A has already occurred.</em></u>

Now, as we can see, from the sample space, only 11 events out of the 30 are the events of interest to us. This is shown in bold below:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

Thus, the probability that the event B occurs given that the event A has already occurred is:

P(B|A)=\frac{11}{30}\approx0.367

In percentage the required probability is 36.7% approximately.

3 0
3 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
In large cities people out and take taxis to get from one place to another the cost is $25.20 every 36 miles how much is a 47 mi
Kay [80]

47 miles taxi ride will cost $32.9

Step-by-step explanation:

Given,

Cost every 36 miles = $25.20

Cost of one mile = \frac{Cost\ for\ 36\ miles}{36}

Cost of one mile = \frac{25.20}{36}\\

Cost of one mile = $0.7

Cost of 47 miles = Cost of one mile * 47

Cost\ of\ 47\ miles = 0.7*47\\Cost\ of\ 47\ miles = \$32.9

47 miles taxi ride will cost $32.9

Keywords: Division, multiplication

Learn more about multiplication at:

  • brainly.com/question/10879401
  • brainly.com/question/10940255

#LearnwithBrainly

5 0
3 years ago
In the equation below, variables X and Y represent two matrices. Which property of matrix addition is illustrated below? x+y=y+x
saw5 [17]
If [x] and [y] are matrices and
[x]+[y] = [y]+[x], then

(a) the matrices have the same number of rows and columns,
(b) the operation of matrix addition is commutative.

Answer: commutative
3 0
3 years ago
Read 2 more answers
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