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3 years ago

State three reasons why an airborne pollutant might be deposited close to its source

Chemistry

1 answer:

den301095 [7]3 years ago

3 0

Explanation:

Air borne pollutants are usually very light particles that are usually carried in the air in the atmosphere. Some of these pollutants can be carried far away and some are found close to their sources.

Some of the factors are:

Wind pressure: if wind pressure is low, pollutants will not be carried far away. In this situation, the particles will be blown and carried over a short distance from their sources. When wind pressure is very high, pollutants will be carried extensively into farther areas.
Pollutants can be trapped in snow. In a snowy area, when pollutants reach sky high and enters condensed water in the atmosphere, they can become super cooled into ice and fall back within the same area where they are formed.
Rain water can also cause pollutants to be dispersed within a short area. Pollutants can mix with rain water and carrier back to the area where they were originally formed.

Learn more:

Pollution brainly.com/question/10743354

#learnwithBrainly

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On which side of an equation are the reactants found?

koban [17]

The reactants are found on the Left of the arrow :)

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3 years ago

The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3

Oksanka [162]

Answer : The mass of $NaN_3$ required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $N_2$ gas = 1.00 atm

V = Volume of $N_2$ gas = 113 L

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $85^oC=273+85=358K$

Putting values in above equation, we get:

$1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K$

$n=3.84mol$

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced reaction we conclude that

As, 3 mole of $N_2$ produced from 2 mole of $NaN_3$

So, 3.84 moles of $N_2$ produced from $\frac{2}{3}\times 3.84=2.56$ moles of $NaN_3$

Now we have to calculate the mass of $NaN_3$

$\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3$

Molar mass of $NaN_3$ = 65 g/mole

$\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g$

Therefore, the mass of $NaN_3$ required is, 166.4 grams.

3 0

3 years ago

Use the given relationship to calculate the ionization energy of a thallium atom, given that radiation of 58.4 nm produces elect

Elenna [48]

The ionization energy is 1 × 10^-18 J

<h3>What is ionization energy?</h3>

The ionization energy is the energy required to remove an electron from an atom.

We have the following information;

wavelength of the photon = 58.4 nm

Speed of the electron = 2310 × 10^3 m/s

Since;

hv = I + 1/2mv^2

v = c/λ

hc/λ = I + 1/2mv^2

I = hc/λ - 1/2mv^2

I = (6.6 × 10^-34 × 3 × 10^8/58.4 × 10^-9) - (1/2 × 9.11 × 10^-31 × (2310 × 10^3)^2)

I = 1 × 10^-18 J

Learn more about ionization energy: brainly.com/question/16243729

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2 years ago

Fossil fuels became an important energy source during the

kvv77 [185]

mid-1700s during the Industrial Revolution

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3 years ago

Read 2 more answers

what mass of sodium chloride is produced when chlorine gas reacts with 0.29 grams of sodium iodide? working on stoichiometry and

Yanka [14]

CI2 + 2Nal ---> 2NalCI + I2
Nal = 149.9 g/mol.
NaCI = 58.5 g/mol
2 mol Nal makes 2 mol NaCI
0.29 g Nal x ( 1 mol / 149.9 g) = 0.0019 mol NaCI
00.19 mol NaCI x ( 58.5 g / 1 mol ) 0.11 g NaCI ( 2 sig figs)

4 0

4 years ago