Question

Use the given relationship to calculate the ionization energy of a thallium atom, given that radiation of 58.4 nm produces electrons with a speed of 2310 km⋅s−1. Note that 1 J=1 kg⋅m2⋅s−2.

Answer 1

The ionization energy is 1  × 10^-18 J

What is ionization energy?

The ionization energy is the energy required to remove an electron from an atom.

We have the following information;

wavelength of the photon = 58.4 nm

Speed of the electron = 2310 × 10^3 m/s

Since;

hv = I + 1/2mv^2

v = c/λ

hc/λ =  I + 1/2mv^2

I = hc/λ  - 1/2mv^2

I = (6.6 × 10^-34 × 3 × 10^8/58.4 × 10^-9) - (1/2 × 9.11 × 10^-31 × (2310 × 10^3)^2)

I = 1  × 10^-18 J

Learn more about ionization energy: brainly.com/question/16243729