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4 years ago

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5 0

Acids and bases are two types of corrosive substances. Any substance with a pH value between 0 up to 7 is considered acidic, whereas a pH value of 7 to 14 is a base. Acids are ionic compounds that break apart in water to form a hydrogen ion (H+).

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Suppose of barium acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of barium cati

ollegr [7]

Explanation:

Let us assume that the given data is as follows.

mass of barium acetate = 2.19 g

volume = 150 ml = 0.150 L (as 1 L = 1000 ml)

concentration of the aqueous solution = 0.10 M

Therefore, the reaction equation will be as follows.

$Ba(C_{2}H_{3}O_{2})_{2} \rightarrow Ba^{2+} + 2C_{2}H_{3}O^{-}_{2}$

Hence, moles of $C_{2}H_{3}O^{-}_{2}$ = $2 \times Ba(C_{2}H_{3}O_{2})_{2}$ .......... (1)

As, No. of moles = $\frac{mass}{\text{molar mass}}$

Hence, moles of $Ba(C_{2}H_{3}O_{2})_{2}$ will be calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{2.19 g}{255.415 g/mol}$ (molar mass of $Ba(C_{2}H_{3}O_{2})_{2}$ is 255.415 g/mol)

= $8.57 \times 10^{-3}$

Moles of $C_{2}H_{3}O^{-}_{2}$ = $2 \times 8.57 \times 10^{-3}$

= 0.01715 mol

Hence, final molarity will be as follows.

Molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{0.01715 mol}{0.150 L}$

= 0.114 M

Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.

5 0

3 years ago

You perform a single extraction with 100 mL of chloroform to remove compound A from 100 mL of an aqueous solution. The partition

Mice21 [21]

Answer:

Percentage of mass of solute in aqueous phase is 28.57%.

Explanation:

$(q)_{aq}$ - Fraction of solute in aqueous phase.

$(q)_{aq}=\frac{V_{aqueous}}{DV_{organic}+V_{aqueous})}$

$V_{aqueous}$ = Used volume of aqueous solution

$V_{organic}$ = Used volume of organic solution

D = partition coefficient.

$(q)_{aq}=\frac{100ml}{(2.5\times100)+100\,ml}=0.2857$

Mass of solute in aqueous phase = $0.2857\times 5g=1.428g$

$Mass\,percentage = \frac{1.428}{5.0}\times 100=28.57$

Therefore, Percentage of mass of solute in aqueous phase is 28.57%.

5 0

3 years ago

G Calculate the mass, in grams, of 225.0 atoms of cadmium, Cd (1 mol of Cd has a mass of 112.41 g).

serious [3.7K]

Please please thank you lord lord thank

3 0

3 years ago

A sample of oxygen gas has a volume of 5.60 l at 27Â°c and 800.0 torr. how many oxygen molecules does it contain?

ratelena [41]

1.44x10^23 molecules of oxygen gas The ideal gas law is PV = nRT where P = pressure (800.0 Torr) V = volume (5.60 L) n = number of moles R = Ideal gas constant (62.363577 L*Torr/(K*mol) ) T = absolute temperature (27C + 273.15 = 300.15 K) Let's solve for n, the substitute the known values and solve. PV = nRT PV/RT = n (800.0 Torr*5.60 L)/(62.363577 L*Torr/(K*mol)*300.15 K) = n (4480 L*Torr)/(18718.42764 L*Torr/mol) = n 0.239336342 mol = n So we have 0.239336342 moles of oxygen molecules. To get the number of atoms, we need to multiply by avogadro's number, so: 0.239336342 * 6.0221409x10^23 = 1.44x10^23

8 0

3 years ago

Complete combustion of wax takes place in____ zone of a candle flame.

Art [367]

Answer:

outer or non - luminous

Explanation:

complete combustion of wax takes place in non-luminous zone of a candle flame.

8 0

3 years ago

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