A local pizzeria sold 65 pizzas yesterday. Suppose the actual number of pizzas sold today was 60. Describe
1 answer:
You might be interested in
Answer:
Question 9
(a) The distance, Jalaj walks in one day is 4.4 km
(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8
Question 10
(b) The difference between the largest and smallest areas is 2,400 m²
Step-by-step explanation:
Question 9
(a) The distance Jalaj walks in 5 days = 22 km
Whereby Jalaj walks equal distance every day, we have;
The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day
The distance, Jalaj walks in one day = 4.4 km
(b) The amount he raises for every kilometer he walks = $1.60
The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60 = $8
Question 10
(b) The given side length of the square = 120 meters to the nearest 10 meters
Therefore;
The maximum dimension for the side length of the square = 120 + 10/2 = 125
The largest possible area of the square, = 125 m × 125 m = 15,625 m²
The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m
The smallest possible area of the square, = 115 m × 115 m = 13,225 m².
The difference between the largest and smallest areas, -
= 15,625 - 13,225 = 2,400 m².
This question is incomplete, the microstates table is left out which will be uploaded along this answer;
Answer:
a) the required is 65.6%
b) the required time is 4.2666 hrs
Step-by-step explanation:
using the microstates from the table in the diagram;
a)
the percent times the above any of the above microstates occurs is;
% (6 heads and 4 tails, 5 heads and 5 tails, 4 heads and 6 tails)
= ((210 + 252 + 210)/1024) × 100
= 0.6562 × 100
= 65.6%
Therefore the required is 65.6%
b)
the probability of getting 10 heads and 0 tail or 0 tail head and 10 tails is;
p( 10H, 0T or 0H, 10T = 2/1024
= 1/512
so on average, it will take 512 trails or at a rate of 2 trials/min, 256 mim in hours;
(256 min) ( 1h/60min) = 4.2666 hrs
Therefore the required time is 4.2666 hrs
