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3 years ago

V+5+9v-9 what’s the answer

Mathematics

2 answers:

Luda [366]3 years ago

5 0

Answer:

-4+10v

Step-by-step explanation:

V125BC [204]3 years ago

4 0

Answer:

10v - 4

Step-by-step explanation:

Next time please provide the instructions (which in this case are "simplify the following expression").

To do this, combine "like terms" in v+5+9v-9.

We get:

10v - 4 (answer)

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The class sizes of the introductory psychology courses at a college are shown below 121,134,106,93,149,130,119,128 the college a

frozen [14]

Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,

(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.

3 0

4 years ago

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How do I find the answer to this problume−9−13+2+13minus, 9, minus, 13, plus, 2, plus, 13.

Whitepunk [10]

Answer:

Answer: 12

Step-by-step explanation:

4 0

3 years ago

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lines a, b, c and d are in the same plane. line a is parallel to line c. lines b and c are perpendicular to line d. based on thi

Natalka [10]

Since the others are congruent and linear so is a and b!!!!!!!!

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3 years ago

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Karen wants to advertise how many chocolate chips are in each big chip cookie at her bakery. she randomly selects a sample of 69

Tomtit [17]

Answer: $(10.1989,\ 11.0011)$

Step-by-step explanation:

Given : Sample size : n=69

Sample mean : $\overline{x}=10.6$

Standard deviation : $s=1.7$

Significance level : $\alpha:1-0.95=0.05$

Then , Critical value : $z_{\alpha/2}=1.96$

The formula to confidence interval is given by : -

$\overline{x}\pm z_{\alpha/2}\dfrac{s}{\sqrt{n}}\\\\\Rightarrow\ 10.6\pm (1.96)\dfrac{1.7}{\sqrt{69}}\\\\\approx10.6\pm0.4011=(10.6-0.4011,10.6+0.4011)=(10.1989,\ 11.0011)$

Hence, the 95% confidence interval for the number of chocolate chips per cookie for big chip cookies= $(10.1989,\ 11.0011)$

8 0

4 years ago

Can someone please help me?

zalisa [80]

21 89(33)222)

Step-by-step explanation:

first i did somthing and tgen i add so got the answer

7 0

4 years ago