Answer: (the function is 8^X, not 8X.)
Step-by-step explanation:
X = 1 8^X = 8
X = 2 8^X = 64
X = 3 8^X = 512
X = 4 8^X = 4096
It does. Because 6+(-1) equals 5 and so does 19-14
ok
we are ask for measuring of center
there are 3 different measures
mode, when the data value occurs the most frequently
median, is the data value in the middle of a sorted list of data
mean is the average of the numbers
so the answer is A) mean and median
The weight of the hamburger is 160g after two bites.
Each bite takes away 20% of the weight of the burger, so we'll divide the initial weight by a percentage to find the weight before the bite.
The starting weight is 160g. Because 20% of the weight was removed from a bite, we'll divide this weight by the percentage of the burger remaining after the bite:

80% of the burger is left after a bite. Convert this fraction into a decimal by dividing by 100:

Divide the initial weight by this decimal:

The weight of the burger before the second bite was 200.
We'll do the same procedure for the first bite. The initial weight is 200, and there is 80% of the burger remaining after the first bite. Because 80% is 0.8 in decimal form, divide 200 by 0.8:

The starting weight of the burger before the bites was
250 grams.
Answer:
B
Step-by-step explanation:
just think about it :
can it move up or down ? no, because for a specific input value still the same functional result is calculated (nothing is getting bigger or smaller).
all that is happening that way is that now, with using g(x), the original f(x) functional values happen now 2 units "later" = to the right (if you consider the x-axis a time line growing to the right). we are getting the functional value of f(x-2) at x and not at x-2 for g(x).
for example
the functional values are for x² (just some integers to make it easier) :
x = 1, 2, 3, 4, 5, ...
getting
f(1), f(2), f(3), f(4), f(5), ...
leading to
1², 2², 3² 4², 5², ...
which is
1, 4, 9, 16, 25, ...
now, let's say we start looking at x = 3
x = 3, 4, 5, 6, 7, ...
getting
g(3), g(4), g(5), g(6), g(7), ..
leading to
1², 2², 3² 4², 5², ...
which is
1, 4, 9, 16, 25, ...
so, now we are getting the functional value at e.g. x = 5 that we got originally for x = 3 (9).
therefore, under g(x) the original functional values still "happen", they just simply "happen" 2 units "later" (to the right).
in the same way
g(x) = f(x+2) moves everything 2 units to the left (now things are happening "earlier").