So if you want to add
we distribute
a(b+c)=ab+ac so
-2(m+n-4)=-2m-2n+8
5(-2m+2n)=-10m+10n
n(m+4n-5)=mn+4n^2-5n
so total we ahve
-2m-2n+8-10m+10n+mn+4n^2-5n
group like terms
4n^2+-2m-10m-2n+10n-5n+mn+8
add like temrs
4n^2-12m+3n+mn+8
Answer:
<h2>
3p+6
</h2>
Step-by-step explanation:
8p+7−(5p+1)
=8p+7+−1(5p+1)
=8p+7+−1(5p)+(−1)(1)
=8p+7+−5p+−1
=8p+7+−5p+−1
=(8p+−5p)+(7+−1)
=3p+6
and thats how you get the answer
---------------------------------
Three consecutive odd integers are n, n+2 and n+4
n + n+2 + n+4 = -87
3n + 6 = -87
3n = -87 - 6
3n = -93
n = -93/3
n = -31
n+2 = -31 + 2 = -29
n+4 = -31 + 4 = -27
The numbers are -31, -29 and -27
300/250 = 6/5
1/5 = 20%
You are correct, well done.
