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3 years ago

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Tracy was given a bag of 250 colored marbles .She randomly chose marble , recorded its color in the table ,and returned it to th

e bag .after doing this 50 times,Tracy has the following data .which statement about the bag of marbles is not supported by the data

1 answer:

jok3333 [9.3K]3 years ago

5 0

Answer:

Did you ever figured it out?

Step-by-step explanation:

?

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Which sequence of transformations will change figure PQRS to figure P′Q′R′S′?

alexandr402 [8]

I think it is the third one. If it’s not the third one then it’s the first one.

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3 years ago

Read 2 more answers

The mean of five numbers is 25, what is their sum?

zubka84 [21]

125 is the answer.

A mean of vie numbers is 25. If it is 25, the numbers must be 25. So, since there is 5 of 25, multiply 25 by 5. Then, the answer would be 125.

There is also another way to do it. Set-up your equation.

x/5=25.

Now flip it to make the equation a multiplication problem.

25×5=x

Once you solve the equation, you should get 125 is the answer.

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3 years ago

Gabby makes banana bread at her bakery every Monday and Wednesday,

garri49 [273]

Answer:

Monday:

<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><em>3</em>

<em>Tablespoon</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><u><em>3</em><em>0</em></u>

<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><u><em>7</em><em>5</em></u>

Wednesday

<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><u><em>1</em><em>.</em><em>1</em><em>2</em></u>

<em>Tablespoons</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em>

<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><em>2</em><em>8</em>

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3 years ago

Q. Find the area of the figure. 10 cm2 12 cm2 20 cm2 24 cm2

likoan [24]

Answer:

$24cm^{2}$

Hope This Helps! :) Please give Brainliest if it does!

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2 years ago

Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$

The equation is true for both roots.

<u>Answer</u>

$\large \boxed {3 {x}^{2} - 14x - 5 = 0}$

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3 years ago