All categories

3 years ago

(-2) 3 = plz help me I need help I need help I need help I need help

Mathematics

2 answers:

Degger [83]3 years ago

5 0

Answer:

-6 is your answer.

Step-by-step explanation:

(-2)(-2)(-2)= -6

xeze [42]3 years ago

4 0

Answer:

To begin with, (-2)3

Which in this case this means multiply

so.. (-2) x 3 = -6

So (-6) would be your answer

Hope i helped!

You might be interested in

2 PUIHS

tatiyna

Answer:

45%

Step-by-step explanation:

3 0

3 years ago

Which expression is equivalent to 3x5x5x5x5x5x5?

lana66690 [7]

Answer:

3*5^6

Step-by-step explanation:

5 0

3 years ago

A butcher has 10 3/4 pounds of ground beef that will be priced at 3.40 dollars per pound. He divides the meat into 8 equal packa

spin [16.1K]

Well we know that 10 and 3/4 is equivalent to 10.75. If we divide the meat into 8 equal packages we have to divide 10.75 by 8. Dividing 10.75 by 8 gives us 1.34375 pounds of meat per package. If we take that, and multiply it by our given value of $3.40 per pound, we end up getting $4.57 a package.

8 0

3 years ago

Read 2 more answers

Holly bought blank CD's and spent $34.57.What is that amount rounded to the nearest dollar?.

Tamiku [17]

Answer:

$35

Step-by-step explanation:

Rounding to the nearest dollar which would be 4 so in that case you would use the 5 in .57 and because 5 is a large number it would make the 4 into a five thus making it $35. Hope this helped :)

3 0

3 years ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

3 years ago