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Rus_ich [418]
2 years ago
11

(-2) 3 = plz help me I need help I need help I need help I need help

Mathematics
2 answers:
Degger [83]2 years ago
5 0

Answer:

-6 is your answer.

Step-by-step explanation:

(-2)(-2)(-2)= -6

xeze [42]2 years ago
4 0

Answer:

To begin with, (-2)3

Which in this case this means multiply

so..  (-2) x 3 = -6

So (-6) would be your answer

Hope i helped!

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To test μ for an x distribution that is mound-shaped using sample size n ≥ 30, how do you decide whether to use the normal or st
Luden [163]
Answer:
Use the normal distribution if the population standard deviation is known.
Use the student's t distribution when the population standard deviation is unknown.

Explanation:
A mound-shaped distribution refers to the normal distribution.
A good sample size for testing against the normal distribution should be
n >= 30.
The condition for the sample size is satisfied.
However, we are not given the population standard deviation, therefore it is assumed to be unknown.
Therefore the student's t distribution should be used. 
6 0
3 years ago
your friend is choosing between two music download companies. MyTunes charges $2.50 per song. Great Songs charges $1.50 per song
vichka [17]

Answer:

After 100 songs

Step-by-step explanation:

2.50x=1.50x+50

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÷.50

X=100

4 0
3 years ago
Need help solving for X
Stels [109]
I hope this helps you



x=108/6


x=18

4 0
3 years ago
Graph the line with slope -1/3 passing through the point (2, 1).
bogdanovich [222]

Answer:

Step-by-step explanation:

y = mx + b

y = -x/3 + b

1 = -2/3 + b

b = 5/3

y = -x/3 + 5/3

5 0
2 years ago
(9x+2)(4x^2+35x-9)=0
pychu [463]
(9x+2)*(4x^2+35x-9)=0

we can make this...

9x+2=0

and

4x^2+35x-9=0

then...

9x+2=0

\boxed{x=-\frac{2}{9}}


4x^2+35x-9=0

x=\frac{-b\pm\sqrt{b^2-4*a*c}}{2*a}

x=\frac{-35\pm\sqrt{35^2-4*4*(-9)}}{2*4}

x=\frac{-35\pm\sqrt{1369}}{8}

x=\frac{-35\pm37}{8}

x_1=\frac{-35+37}{8}=\frac{1}{4}

x_2=\frac{-35-37}{8}=-9

\boxed{\boxed{S=\{\frac{1}{4},-\frac{2}{9},-9\}}}

I'm sure about my answer, don't matter the order...
4 0
2 years ago
Read 2 more answers
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