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melamori03 [73]
3 years ago
11

WILL MARK BRAINLIEST TO THE FIRST PERSON

Mathematics
2 answers:
WINSTONCH [101]3 years ago
6 0

Answer:

5

Step-by-step explanation:

7^2 = (2(6)^1/2)^2 + BC^2 (Pyth. theorem)

BC = 5

maxonik [38]3 years ago
5 0

Answer:

its supposed to be 6.08 but we can take of..08 so 6

Step-by-step explanation:

a + b = c \\ ( 2  \sqrt{6} )  {}^{2}   +  {b}^{2}  =  {7}^{2}  \\ 2 \times 6 +  {b}^{2}  = 49 \\  {b}^{2}  = 49 - 12 \\  {b }^{2}  = 37 \\  \sqrt{b}  {}^{2}  =  \sqrt{37}  \\ b = 6.08 \: or \: 6

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A sample of size 45 will be drawn from a population with mean 53 and standard deviation 11. Use the TI-84 Plus calculator. (a) I
sukhopar [10]

Answer:

a) We have the standard deviation and the mean, so it is appropriate to use the normal distribution to find probabilities for x.

b) There is a 15.97% probability that x will be between 54 and 55.

c) The 47th percentile of x is X = 52.877.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

A sample of size 45 will be drawn from a population with mean 53 and standard deviation 11.

This means that \mu = 53.

We have to find the standard deviation of the sample, that is:

\sigma = \frac{11}{\sqrt{45}} = 1.64

(a) Is it appropriate to use the normal distribution to find probabilities for x?

We have the standard deviation and the mean, so it is appropriate to use the normal distribution to find probabilities for x.

(b) Find the probability that x will be between 54 and 55.

This is the pvalue of the Z score when X = 55 subtracted by the pvalue of the Z score when X = 54.

X = 55

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 53}{1.64}

Z = 1.22

Z = 1.22 has a pvalue of 0.88877.

X = 54

Z = \frac{X - \mu}{\sigma}

Z = \frac{54 - 53}{1.64}

Z = 0.61

Z = 0.61 has a pvalue of 0.72907.

So, there is a 0.88877 - 0.72907 = 0.1597 = 15.97% probability that x will be between 54 and 55.

(c) Find the 47th percentile of x. Round the answer to at least two decimal places.

This is the value of X when Z has a pvalue of 0.47;

This is between Z = -0.07 and Z = -0.08. So we use Z = -0.075.

Z = \frac{X - \mu}{\sigma}

-0.075 = \frac{X - 53}{1.64}

X = 52.877

The 47th percentile of x is X = 52.877.

8 0
3 years ago
Please help how do i find the area of the shape?
Orlov [11]

Answer:

Do not listen to the other answer! Here is how you solve that.

Step-by-step explanation:

For the semicircle, here is the formula for area: A= \frac{1}{2}(\pi r^2)

For the triangle, here is the formula for area:A=\frac{1}{2}(bh)

Then, add.

So,

Triangle:

A=\frac{1}{2}(9*12)

A=54

Semicircle:

A=\frac{1}{2}(\pi 6^2)

A=18\pi

Your answer is Area = 54 + 18\pi

6 0
3 years ago
10 POINTS!!: ANSWER THIS QUESTION<br> (please no bad answers)
nevsk [136]

Answer:

Write in standard form.

3x+2y=8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the volume of a box with sidelines that are 20 inches use the formula B equals S3 where is S is the length of one side
anastassius [24]

Answer:

The volume of a box with sidelines that are 20 inches is 8000 cubic inches

Step-by-step explanation:

The volume of a box with sidelines that are 20 inches can be determined by using the formula

B = S³

Where S is the length of one side

and B is the Volume

From the question, the sidelines of the box are 20 inches. That is

S = 20 inches

From

B = S³

B = (20 inches)³

B = 20 inches × 20 inches × 20 inches

B = 8000 cubic inches

Hence, the volume of a box with sidelines that are 20 inches is 8000 cubic inches.

4 0
3 years ago
A. Decide whether the given examples illustrate a constant or a variable.
notka56 [123]

Answer:

a constant is a data item whose value cannot change during the program execution just as its name implies that the value is constant a variable is a data item whose value can change during the program's execution . Thus as its name implies the the value can vary

5 0
2 years ago
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