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timurjin [86]
3 years ago
14

A publisher wants to figure out how thick their new book will be. The book has a front cover and a back cover, each of which hav

e a thickness of of an inch. They have a choice of which type of paper to print the book on.
Bond paper has a thickness of inch per one hundred pages. Write an equation for the width of the book, , if it has hundred pages, printed on bond paper.
Mathematics
1 answer:
denpristay [2]3 years ago
5 0

Answer:

1in. x 2 + 1in. = 3in.

Step-by-step explanation:

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Mrac [35]

Answer:

i think its

5 + 4y

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5 0
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Write as a mixed number 98/5
Reptile [31]

Answer:

The answer is 19.6 or 1 9/6 hope this helps!

Step-by-step explanation:

4 0
3 years ago
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An isosceles right triangle has a hypotenuse of length e. Select all that are true for the triangle.
____ [38]
<h3>2 Answers: </h3>
  • Choice C) Leg length = \frac{e\sqrt{2}}{2}
  • Choice E) Area = \frac{e^2}{4}

Note: if the formulas don't load properly, then you may need to refresh the page.

======================================================

Explanation:

For any 45-45-90 right triangle, the hypotenuse H is always sqrt(2) times the leg L

In terms of symbols, we can say

H = L*\sqrt{2}

We're told the hypotenuse is e, so H = e

Let's solve for L in terms of e

H = L*\sqrt{2}\\\\e = L*\sqrt{2}\\\\L*\sqrt{2} = e\\\\L = \frac{e}{\sqrt{2}}\\\\

Now let's multiply top and bottom by \sqrt{2} to rationalize the denominator

L = \frac{e}{\sqrt{2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{2}*\sqrt{2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{2*2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{4}}\\\\L = \frac{e\sqrt{2}}{2}\\\\

If the hypotenuse is e, then the length of each leg is \frac{e\sqrt{2}}{2}

This matches with choice C, which is one of the two answers. This allows us to rule out choices A and B, as those expressions are not equivalent to the expression for choice C.

----------------

The two legs of any right triangle form the base and height. The order doesn't matter. The base is always perpendicular to the height. In a right triangle, the two legs are always perpendicular.

The base and height are \frac{e\sqrt{2}}{2} each.

The area of the triangle is...

\text{Area} = \frac{1}{2}*\text{base}*\text{height}\\\\\text{Area} = \frac{1}{2}*\frac{e\sqrt{2}}{2}*\frac{e\sqrt{2}}{2}\\\\\text{Area} = \frac{e\sqrt{2}*e\sqrt{2}}{2*2*2}\\\\\text{Area} = \frac{e*e\sqrt{2*2}}{2*2*2}\\\\\text{Area} = \frac{e^2\sqrt{4}}{2*2*2}\\\\\text{Area} = \frac{e^2*2}{2*2*2}\\\\\text{Area} = \frac{e^2}{2*2}\\\\\text{Area} = \frac{e^2}{4}\\\\

This matches with choice E, which is the other answer. Choices D and F are eliminated as they are not equivalent to the expression for choice E.

4 0
3 years ago
The heights in inches of orangutans Are normally distributed with a population standard deviation of 3" and an unknown populatio
CaHeK987 [17]

Answer: The 95% confidence interval is approximately (55.57, 58.43)

======================================================

Explanation:

At 95% confidence, the z critical value is about z = 1.960 which you find using a table or a calculator.

The sample size is n = 17

The sample mean is xbar = 57

The population standard deviation is sigma = 3

The lower bound of the confidence interval is

L = xbar - z*sigma/sqrt(n)

L = 57 - 1.960*3/sqrt(17)

L = 55.5738905247863

L = 55.57

The upper bound is

U = xbar + z*sigma/sqrt(n)

U = 57 + 1.960*3/sqrt(17)

U = 58.4261094752137

U = 58.43

Therefore the confidence interval (L, U) turns into (55.57, 58.43) which is approximate.

7 0
3 years ago
Will mark branliest<br><br> combine like terms to create an equivalent expression to 7(2j + 3 + 2j).
Helga [31]

Answer:

28j + 21

step-by-step explanation:

(7) (2j+3+2j)

=(7*2j) + (7*3) + (7*2j)

=14j + 21 + 14j

=28j + 21

7 0
3 years ago
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