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3 years ago

Can someone explain to me how to do this ?

Mathematics

1 answer:

NeTakaya3 years ago

8 0

Answer:

Step-by-step explanation:

y=-(x³)

take the points x=-2,-1,0,1,2

y=8,1,0,-1,-8

plot the points (-2,8),(-1,1),(0,0),(1,-1),(2,-8)

y=-x²

take the points x= -2,-1,0,1,2

y=-4,-1,0,-1,-4

plot the points (-2,-4),(-1,-1),(0,0),(1,-1),(2,-4)

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Yunika downloaded four applications for $2.99 each to her cell phone. The remaining applications that Yunika purchased cost $1.9

shtirl [24]

The answer would be C. She bought four applications for 2.99 each. you would multiply 2.99 x 4 to get 11.96. X would be the variable and we don’t know how many apps she bought for 1.99 so we would do 1.99 by however many apps she bought and 11.96 of the four apps she bought to find the total. this gets the answer of y = 1.99x + 11.96

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4 years ago

What is 4.5(5.6*2)+1.2?

worty [1.4K]

$\boxed{51.6}$

To solve this, we will first use order of operations to multiply the terms inside the parentheses, multiply the product by the term outside of the parentheses, and then add from left to right.

5.6 * 2 = 11.2

11.2 * 4.5 = 50.4

50.4 + 1.2 = 51.6

Therefore, 51.6 is the solution.

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4 years ago

Read 2 more answers

Gas mileage is the number of miles you can drive on a gallon of gasoline. A test of a new car results in 460 miles o. 20 gallons

Nezavi [6.7K]

Answer:

1,610 miles

Step-by-step explanation:

If you do 460/20 you get the gas mileage. The gas mileage is 23. If you do 23*70 you get 1610 miles out of 70 gallons of gas. (Double-check to make sure I'm correct)

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3 years ago

: If tan A=- 9/13 and 0 < A < 180, find, without using tables or calculators, the value of

stich3 [128]

Answer: $\bold{\sin A=\dfrac{9\sqrt{10}}{50}\qquad \cos A=-\dfrac{13\sqrt{10}}{50}}$

<u>Step-by-step explanation:</u>

0° < A < 180° so it is in Quadrant I or II

since tan A is negative, it is in Quadrant II ---> (-x, +y)

$\text{Given}:\tan A=\dfrac{y}{x}\ =\dfrac{9}{-13}$

Next, find the hypotenuse given that x = -13 and y = 9

(-13)² + (9)² = r²

250 = r²

5√10 = r

$\sin A = \dfrac{y}{r}\quad =\dfrac{9}{5\sqrt{10}}\bigg(\dfrac{\sqrt{10}}{\sqrt{10}}\bigg)\quad =\large\boxed{\dfrac{9\sqrt{10}}{50}}\\\\\\\\\cos A = \dfrac{x}{r}\quad =\dfrac{-13}{5\sqrt{10}}\bigg(\dfrac{\sqrt{10}}{\sqrt{10}}\bigg)\quad =\large\boxed{-\dfrac{13\sqrt{10}}{50}}$