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Galina-37 [17]
3 years ago
12

Determine the vertex of the function f(x) = 2(x-4)^2+5

Mathematics
1 answer:
spayn [35]3 years ago
5 0

Answer:

(4,5)

Step-by-step explanation:

The vertex is written in vertex form.

y = a(x - b)^2 + c

Vertex: (b,c)  Notice the sign change on b.

So for your equation, you get (4,5) No sign change on the 5.

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Write an expression from the description. Then
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(-36 ÷ -4) + 9

The expression equals 18.

4 0
3 years ago
Find the value of this expression if x = -9.<br> x2 + 3<br> x +6
iren [92.7K]

Answer:

Step-by-step explanation:

x² + 3 = (-9)² + 3          {  (-9)² = -9 *-9 = 81}

     = 81 + 3

       = 84

x + 6 = -9 + 6 = -3

7 0
3 years ago
Round this number to the nearest tenth 4.9675
MatroZZZ [7]
Add half a tenth.
.. 4.9675 +0.05 = 5.0175
Throw away all the digits to the right of the tenths digit.
.. 5.0

Your rounded number is 5.0
8 0
3 years ago
Item 21
Pavlova-9 [17]

Answer:

1st: 5x

2nd: 6ft

Step-by-step explanation:

I really don't know how just got the answer right.

5 0
3 years ago
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h
Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

P(t) = P(0)(1+r)^{t}

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that r = 0.047

$172000 in 2004

This means that P(0) = 172000

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

P(t) = P(0)(1+r)^{t}

249000 = 172000(1.047)^{t}

(1.047)^{t} = \frac{249000}{172000}

\log{(1.047)^{t}} = \log{\frac{249000}{172000}}

t\log(1.047) = \log{\frac{249000}{172000}}

t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}

t = 8.05

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

8 0
3 years ago
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