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3 years ago

Determine the vertex of the function f(x) = 2(x-4)^2+5

Mathematics

1 answer:

spayn [35]3 years ago

5 0

Answer:

(4,5)

Step-by-step explanation:

The vertex is written in vertex form.

y = a(x - b)^2 + c

Vertex: (b,c) Notice the sign change on b.

So for your equation, you get (4,5) No sign change on the 5.

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Write an expression from the description. Then

vodka [1.7K]

(-36 ÷ -4) + 9

The expression equals 18.

4 0

3 years ago

Find the value of this expression if x = -9.<br> x2 + 3<br> x +6

iren [92.7K]

Answer:

Step-by-step explanation:

x² + 3 = (-9)² + 3 { (-9)² = -9 *-9 = 81}

= 81 + 3

= 84

x + 6 = -9 + 6 = -3

7 0

3 years ago

Round this number to the nearest tenth 4.9675

MatroZZZ [7]

Add half a tenth.
.. 4.9675 +0.05 = 5.0175
Throw away all the digits to the right of the tenths digit.
.. 5.0

Your rounded number is 5.0

8 0

3 years ago

Item 21

Pavlova-9 [17]

Answer:

1st: 5x

2nd: 6ft

Step-by-step explanation:

I really don't know how just got the answer right.

5 0

2 years ago

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h

Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that $r = 0.047$

$172000 in 2004

This means that $P(0) = 172000$

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

$P(t) = P(0)(1+r)^{t}$

$249000 = 172000(1.047)^{t}$

$(1.047)^{t} = \frac{249000}{172000}$

$\log{(1.047)^{t}} = \log{\frac{249000}{172000}}$

$t\log(1.047) = \log{\frac{249000}{172000}}$

$t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}$

$t = 8.05$

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

8 0

3 years ago