Answer:
Step-by-step explanation:
We want to find a third degree polynomial with zeros <em>x </em>= 2 and <em>x</em> = 2i and f(-1) = 30.
First, note that by the Complex Root Theorem, since <em>x</em> = 2i is a root, <em>x</em> = -2i must also be a root.
Hence, we will have the three factors:
Where <em>a</em> is the leading coefficient.
Expand and simplify the second and third factors:
Hence:
Since f(-1) = 30:
In conclusion, third degree polynomial function is:
Answer:
f(x) = x² +x -6
Step-by-step explanation:
The standard form will look like ...
f(x) = x² +bx +c
where b is the opposite of the sum of the roots, and c is their product.
f(x) = x² -(-3+2)x +(-3)(2)
f(x) = x² +x -6
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<em>Additional comment</em>
In general, "standard form" is ax²+bx+c. In this case, the coefficient 'a' can be 1 since neither of the roots is expressed as a fraction. The sum of roots is (-b/a) and the product of roots is (c/a).
Answer:x
xhxxfhhhxhxfghghfxf
Step-by-step explanation:hgxfhgh
xhfxfhxfhxfhhxffhx
Answer:
<em>3^2 ; Option B</em>
Step-by-step explanation:
We are given the equation 3^ -6 * ( 3^4 / 3^0 )^2, which can be solved through the application of exponential rules;
<em>3^2 ; Option B</em>
